PHP - 从JSON数组中获取变量

Question

I am using a PHP library (Abraham's OAUTH) as an app to connect to my twitter account and I am pulling down my own tweets from Twitter's API in an attempt to aesthetically display them on my on page.

I'm looping through them all with a foreach

<?php

foreach ($statuses as $key => $status) {
    echo '
    <blockquote class="twitter-tweet" data-lang="en"><p lang="und" dir="ltr">' . $status->text . '</p>
    ' . $status->name . ' (@' . $status->screen_name . ') <a href="https://twitter.com/' . $status->screen_name . '/status/' . $status->id_str . '">' . $status->created_at . '</a></blockquote><script async src="https://platform.twitter.com/widgets.js" charset="utf-8"></script><br>
    ';
}

?>

These are the from the var_dump and are the ones I am using

array(1) { [0]=> object(stdClass)#3 (25) { ["created_at"]=> string(30) "Fri May 18 10:41:07 +0000 2018" ["id"]=> int(997426852204634112) ["id_str"]=> string(18) "997426852204634112" ["text"]=> string(27) "lol" ["name"]=> string(6) "Example" ["screen_name"]=> string(10) "Example_Name"

However I get returned:

Notice: Undefined property: stdClass::$name

Notice: Undefined property: stdClass::$screen_name

Why is this? I see name and screen_name in the var_dump so why is it not able to pick them up?

Answer 1

It's simply a notice, marking that the structure has no property. You have several solutions:

1. Switch Notice error off (Not recommended) Official php docs

2. Check if the property exists and echo it only if it does. E.g.:

   isset($status->screen_name) ? $status->screen_name : '';
   

3. You can normalize data before output: just initialize the property with a default value if it doesn't exist:

    $status->screen_name = isset($status->screen_name) ? $status->screen_name : '';
   

Update: In your case you try to access the wrong node: "screen_name" is a node of the stdClass object user, which is a child of your status object. So, you need to call $status->user->screen_name.