2015-04-24 13:31
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I have this php code

 $Command = "cd /var/www/html/Codiad/workspace/workspace  2>&1; gcc HelloWorld.c; ./a.out"
 $Method1 = exec($Command);
 echo $Method1;

The code works fine, it shows the output, but I want only see the output after click on a button. How can I do that remaining on the same page? To be more precise I have two buttons, one for compiling code and one for execute it.

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1条回答 默认 最新

  • duanjiao5082 2015-04-24 13:34

    I suggest you do it with AJAX and make 2 calls. One button clicks makes request that will compile. Other will execute the code.

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