duanbei7005 2015-06-17 08:36
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mysqli_result值在php中变量

Echo of facultyname is showing a value but fid is not getting value. I want to assign value of fid to a variable.

$facultyname=$_POST['facultyname'];
echo $facultyname;

$query="SELECT fid FROM faculty WHERE fname='$facultyname'";
$fid_result=mysqli_query ($link,$query);
$finfo = mysqli_fetch_field($fid_result);
 printf("FacultyID :- %d     ",$finfo->fid);
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1条回答 默认 最新

  • duanna2026 2015-06-17 08:40
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    change field to assoc

     $finfo = mysqli_fetch_field($fid_result);
    

    to

    $finfo = mysqli_fetch_assoc($fid_result);
    

    Read - for reference

    Fetch field

    Fetch Assoc

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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