用于iframe变量的PHP preg_replace

Question

I have a widget for users to enter in the code for an iframe widget that is created on another site. There are a few variations of what the iframe code that is generated from the other site will contain, so I want to strip out everything except for the 6 digits that identify the widget, and then echo back the iframe code with the digits inserted.

I'm not sure why this isn't working … The code I have been using is here:

<?php

$widget_id = $vars['entity']->widget_id;

if ($widget_id) {

    $widget_id = preg_replace('<iframe src=(.*?)/widgets/(\d+)(.*?)</iframe>', '$2', $widget_id);

    echo '<iframe src="http://website.com/widgets/'.$widget_id.'/player_universal" width="300" height="250"></iframe>';

}

else {
    echo "Enter the widget short code";
}

Answer 1

This should work for you

$widget_id = preg_replace('/\<iframe src=(.*?)\/widgets\/(\d+)(.*?)\<\/iframe\>/', '$2', $widget_id);

notice the delimiters around the regular expression / reg-exp /
you can make it case-insensitive too by using i modifier / reg-exp /i

you also need to escape all the special reg-exp characters too (see preg_quote() for a list)

See
http://www.php.net/manual/en/function.preg-replace.php
http://www.php.net/manual/en/reference.pcre.pattern.modifiers.php

p.s. / is not the only character you can use, I've seen @ and | too