如果没有值，则使用默认值进行内爆

Question

I want to show dash(-) if my array is empty after imploding it. Here below is my try so far.

Result with Data in Array -> https://repl.it/HIUy/0

<?php 

$array = array(1,2);
$result = array();
foreach ($array as $curr_arr) {

    $result[] = $curr_arr;
}
echo 'Array With Data - ' .  implode(',', $result);
//Result : Array With Data : 1,2   
?>

Result without Data in Array -> https://repl.it/HIVE/0

<?php 

$array = array();
$result = array();
foreach ($array as $curr_arr) {

    $result[] = $curr_arr;
}
echo 'Array Without Data - ' .  implode(',', $result);
//Result : Array With Data - :    
?>

As you can see in the second result, I am unable to print anything as my array was blank hence I was unable to print anything.

However, I want to print Dash(-) using implode only by using something like array_filter which I already tried but I am unable to do so. Here I have tried this https://repl.it/HIVP/0

<?php 

$array = array();
$result = array();
foreach ($array as $curr_arr) {

    $result[] = $curr_arr;
}
echo 'Array With Data : ' .  implode(',', array_filter($result));
//Result : Array With Data :    
?>

Can someone guide me how to achieve this ?

Thanks

Answer 1

You can check if your array is empty and then return/ echo a Dash:

if(!empty($array)){
  // Array contains values, everything ok
  echo 'Array with data - ' . implode('yourGlueHere', $array);
} else {
  // Array is empty
  echo 'Array without data -';
}

If you want to have it in one line, you could do something like the following:

echo 'Array with' . empty($array) == false ? '' : 'out' . 'data - ' . empty($array) == false ? implode('glue', $array) : '';