PHP - 确保数组包含特定键

Question

I have a PHP array like this..

Array
(
    [04] => 1
    [09] => 1
    [10] => 1
    [01] => 1
)

I want to make sure that it has keys 1-10 in it, if they do not exist then I want them to be added with a value of 0, so my final array looks like this..

Array
(
    [01] => 1
    [02] => 0
    [03] => 0
    [04] => 1
    [05] => 0
    [06] => 0
    [07] => 0
    [08] => 0
    [09] => 1
    [10] => 1
)

I am doing it like this..

if (!array_key_exists("01",$myarray)) {
     $myarray['01'] = 0;
}

if (!array_key_exists("02",$myarray)) {
     $myarray['02'] = 0;
}

if (!array_key_exists("02",$myarray)) {
     $myarray['02'] = 0;
}

if (!array_key_exists("03",$myarray)) {
     $myarray['03'] = 0;
}

And so on up until 10, then I do a ksort to get them in the right order

ksort($myarray)

This works but I am aware this is quite clunky and probably not very efficient.

Can anyone point me towards a better solution?

Answer 1

Using functional techniques ends up making your process look convoluted. An important factor in choosing the right solution should be the omission of the ksort() call. If a coding solution is engineered properly, you store the data in the desired order to begin with -- no mopping up after iterating.

Code: (Demo)

$data = ["04" => 1, "09" => 1, "10" => 1, "01" => 1];

for ($x = 1; $x < 11; ++$x) {
    $key = sprintf("%02d", $x);  // ensure proper padding with 0
    $result[$key] = $data[$key] ?? 0;  // null coalescing operator from php5.6+
}

print_r($result);

Output:

Array
(
    [01] => 1
    [02] => 0
    [03] => 0
    [04] => 1
    [05] => 0
    [06] => 0
    [07] => 0
    [08] => 0
    [09] => 1
    [10] => 1
)