使用PHP逐个在MySQL中存储数组

Question

Ii have stored an array list using

<?php
$array = array("foo", "bar", "hello", "world");
include("mydb.php");
$array_string=mysql_escape_string(serialize($array));
mysql_query("insert into tsest (array) values('$array_string')",$con) or die("not updated");
?>

now i want to update that field with a new array but don't delete previeus one i used

   <?php
$array = array("aaa");
include("mydb.php");
$array_string=mysql_escape_string(serialize($array));

$sql= 'select * from tsest where uname = "manoj" ';    
    $result = mysql_query($sql,$con);
    $row = mysql_fetch_array($result);  
$value=$row['array'];
mysql_query('UPDATE tsest SET array="'.$array_string.'"'.$value.' where uname="manoj"',$con) or die("hello");

?>

but it didn't work

Answer 1

You have serialized your array before you store it, but you need to unserialize before you can add to it.

$value=unserialize($row['array']);

You also need to merge the arrays, doing a $array_string.'"'.$value will not work.

Try this:

$newArray = mysql_escape_string(serialize(array_merge($value, $array_string)));
mysql_query('UPDATE tsest SET array="'.$newArray.' where uname="manoj"',$con) or die("hello");