PHP：变量在函数内部不起作用？

Question

echo $path; //working
function createList($retval) {
    echo $path; //not working
    print "<form method='POST' action='' enctype='multipart/form-data'>";
    foreach ($retval as $value) {
            print "<input type='checkbox' name='deletefiles[]' id='$value' value='$value'>$value<br>";
    }
    print "<input class='submit' name='deleteBtn' type='submit' value='Datei(en) löschen'>";
    print "</form>";    
}

what am I doing wrong? why is $path printed correctly outside of the createList function, but it's not accessible inside the function?

Answer 1

Because it's not defined in the function.

There are a few ways to go about this:

1) Use what Alex said by telling the function it is a global variable:

echo $path; // working

function createList($retval) {
  global $path;

  echo $path; // working

2) Define it as a constant:

define(PATH, "/my/test/path"); // You can put this in an include file as well.

echo PATH; // working

function createList($retval) {

  echo PATH; // working

3) Pass it into the function if it's specific to that function:

echo $path; // working

function createList($retval, $path) {

  echo $path; // working

Based on how the function really works, one of those will do ya.