使用define（）时未定义的变量错误

Question

Using PHP 5.4 I am getting 'Notice: Undefined variable: sqliteDatabase in test.php on line 9'

Code:

<?php

//Set The Database Name, No Other Editing Of This File Should Be Done
 define("sqliteDatabase", "PlayerVsPlayerDatabase" );

 //Nothing Below Needs Touched
 date_default_timezone_set('UTC');

 if(!file_exists("${sqliteDatabase}.sqlite3")) {

    try {

        // Create (connect to) SQLite database in file
        $file_db = new PDO("sqlite:${sqliteDatabase}.sqlite3");

Answer 1

Change

if(!file_exists("${sqliteDatabase}.sqlite3")) {

to

if(!file_exists(sqliteDatabase.".sqlite3")) {

A constant should be called without single and double quotes.