I have an html form in which a person fills an input field. The input field will then be sent to the PHP form handler. The form handler will then process it and the variable input in the html form will then become the name of an SQL table. Everything is okay except that part of making the variable the name of SQL table.
Look at my code:
<?php error_reporting(E_ALL); ini_set('display_errors', 1);?>
<?php $title =$_POST['myfile']?>
<?php $info =$_POST['info']?>
<?php $tags =$_POST['tags']?>
<?php $category =$_POST['category']?>
<?php $allowcomments =$_POST['allowcomments']?>
<?php $flagging =$_POST['flagging']?>
<?php $visibility =$_POST['visibility']?>
<?php $date =$_POST['date']?>
<?php $name =$_POST['name']?>
<?php $size =$_POST['size']?>
<?php $type =$_POST['type']?>
<?php $path =$_POST['path']?>
<?php $sub =$_POST['sub']?>
<?php $cap =$_POST['cap']?>
<?php
$servername='localhost';
$username='root';
$password='you aint gonna know my password!!';
$dbname = "galaxall";
$conn = new mysqli($servername, $username, $password, $dbname);
@mysql_select_db('galaxall');
?>
<?php $title =$_POST['myfile']?><br>
<?php echo $title?><br>
<?php echo $info?><br>
<?php echo $tags?><br>
<?php echo $category?><br>
<?php echo $allowcomments?><br>
<?php echo $visibility?><br>
<?php echo $flagging?><br>
<?php echo $cap ?>
<?php echo $date ?>
<?php echo $name ?>
<?php echo $size ?>
<?php echo $type ?>
<?php echo $sub ?>
<?php echo $cap ?>
<?php $file=$_POST['myfile']?>
<?php
$sql="INSERT INTO `galaxall_uploads` (`ID`, `Title`, `Producer`, `Description`, `Tags`, `Type`, `Category`, `Allow comments`, `Flag offensive comments`, `Date`, `Visibility`,`Size`,`Path`,`Subtitles_source`,`Captions_source`) VALUES (NULL, '$title', '', '$info', '$tags', '$type', '$category', '$allowcomments', '$flagging', '$date', '$visibility','$size','$path','$cap','$sub')";
$sql2="CREATE TABLE $title `Comments` ( `ID` BIGINT(255) NOT NULL AUTO_INCREMENT , `Commenter` VARCHAR(255) NOT NULL , `Comment` TEXT NOT NULL , `Date/time` DATETIME NOT NULL , `Likes` BIGINT(255) NOT NULL , `Dislikes` BIGINT(255) NOT NULL , `Replies number` BIGINT(255) NOT NULL , PRIMARY KEY (`ID`)) ENGINE = InnoDB;";
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
?>
<?php
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if ($conn->query($sql2) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql2 . "<br>" . $conn->error;
}
?>
<html>
The file has been uploaded
</html>
The var $title has been declared and I an even echo it.But when i try to make it the name of the table(sql2),I get the error
2018-07-20 New record created successfullyError: CREATE TABLE title `Commentsss` ( `ID` BIGINT(255) NOT NULL AUTO_INCREMENT , `Commenter` VARCHAR(255) NOT NULL , `Comment` TEXT NOT NULL , `Date/time` DATETIME NOT NULL , `Likes` BIGINT(255) NOT NULL , `Dislikes` BIGINT(255) NOT NULL , `Replies number` BIGINT(255) NOT NULL , PRIMARY KEY (`ID`)) ENGINE = InnoDB;
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '`Commentsss` ( `ID` BIGINT(255) NOT NULL AUTO_INCREMENT , `Commenter` VARCHAR(25' at line 1 The file has been uploaded
So how do I make a PHP variable the name of a table?
