DateTime不适用于1970年以前的日期[重复]

Question

This question already has an answer here:

• Create Date object in PHP for dates before 1970 in certain format 1 answer

PHP v 5.6.2

I need to convert dates such as 18-Jul-46 to give me 18/07/1946 and no amount of DateTime functions work correctly. (As strtotime wont work for dates before 1970). They all end up giving 18/07/2046 which is incorrect.

Codes I tried so far:

$date = new DateTime("18-Jul-46");
$date->format('d/m/Y');

Another one with DateTime

$date = DateTime::createFromFormat('d-M-y', "18-Jul-46");
$date->format('d/m/Y');

Earlier also tried,

$date = date('d/m/Y', strtotime('18-Jul-46'));

None of them gave me the correct format. Any pointers or help is appreciated.

Thanks in advance!

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Answer 1

The computer doesn't know whether you mean 2000 or 1900. You can just take the last 2 digits of the year and put "19" before like:

$date = new DateTime("18-Jul-46");
$date->format('d/m/19y');

If you want to use 2000 as well, this code will use the closest number to 1970

$date = new DateTime("18-Jul-20");
$date->format('d/m/Y');
$t1 = $date->format('19y');
$t2 = $date->format('20y');

if(abs(1970-$t1)<abs(1970-$t2))
    echo $t1; //Take the 19.. one
else
    echo $t2; //Take the 20.. one

But in the end, you can't be sure that even 2030 would be correct.