dongliyan9190 2015-02-11 18:48
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PHP:检查图片,视频或声音的值

I have string variable like this:-

$type 

Some time this variable have value ( images ) :-

$type = 'imagename.jpg';
$type = 'imagename.png';
$type = 'imagename.gif';

And some time have value ( audio ) :-

$type = 'audioname.mp3';

And some time have value ( video ):-

$type = 'vname.3gp';
$type = 'vname.flv';
$type = 'vname.mp4';

Now i need to check this var what type is ( Images or Video or Audio )

How can check it ?

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1条回答 默认 最新

  • doulang9953 2015-02-11 20:08
    关注

    This wil echo the type based on the string you defined....

    $typeArr = explode('.', $type);
    
    switch (end($typeArr)){
     case 'jpg':
     case 'png':
     case 'gif':
       echo 'IMAGE';
       break;
     case 'mp3':
       echo 'AUDIO';
       break;
     case '3gp':
     case 'flv':
     case 'mp4':
       echo 'VIDEO';
       break;
     default:
       echo 'NOT DEFINED';
       break;
    }
    
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