使用PHPUnit模拟方法的返回值

Question

I want to mock a method of a class to return specific value:

$this->mock
    ->method('method')
    ->willReturn($this->returnValue('foo'))
;

This method will be invoked internally by another method which will use it's result. The method is actually being mocked but it returns this:

class PHPUnit_Framework_MockObject_Stub_Return#471 (1) {
  protected $value =>
  string(3) "foo"
}

instead of a string. And the code which uses this method internally breaks.

How can I make a mock return a real string instead of this object?

I tried the returnCallback but it returns something even more weird...

PHPUnit v5.7.19

PHP v7.1.4

Answer 1

I used PHPUnit API incorrectly. It should read as follows:

$this->mock
    ->method('method')
    ->will($this->returnValue('foo'))
;

Note ->will instead of ->willReturn.