如何在两个不同的按钮上执行相同的事件？

Question

I have this piece of code below, supposing it will display no request when no data in database and it will display the request with an accept and reject button when they is data in database. How should i write my code in order to make the accept and reject button perform some action?

<?php 

        $travelRequest = $user->userTravelRequest($userid);
        if(!$travelRequest){
            echo '<div class="requestbox">
                  <p> You have no request from others at the moment. </p>
                  </div>';
        }

        else {
            foreach($travelRequest as $request){

                echo '<div class= "requestbox">
                      <p>'. $request->trip_name.'</p>
                      <p>Organised by '.$request->username.'</p>';

        ?>

                      <form method="POST">
                      <div class = "AR-btn">
                      <input type="button" name="accept" value="Accept"/>
                      <input type="button" name="reject" value="Reject"/>
                      <p></p>
                      </div>
                      </form>
                      </div>

        <?php   

            }

        }
        ?>

Answer 1

Use type="submit" instead of type="button", and give them the same name. Then they'll submit the form, and the script can test which button was used from the value of that parameter.

<input type="submit" name="action" value="Accept"/>
<input type="submit" name="action" value="Reject"/>

You then test this with:

if (isset($_POST['action'])) {
    if ($_POST['action'] == 'Accept') {
        // Add to database
    } elseif ($_POST['action'] == 'Reject') {
        // Delete from database
    }
}