I use jQuery Ajax (innerHTML) to generate a listing of records from MySQL database. I would like to put a DELETE
button next to each of these records.
Once you press the DELETE
button, the record will be removed from database and faded away from the displayed list. Is it possible to do it - to nest another jQuery Ajax function in innerHTML output?
Please note that the DELETE
function I use works perfectly fine with standard PHP/HTML output.
In the main php file (test1.php ) I have form to choose a time frame and once form is being submitted function bellow is generating my output in the same file:
<div id="display_taxation_data"></div>
Code responsible for generating listing:
function showDataLabour(str) {
if (str == "") {
document.getElementById("display_taxation_data").innerHTML = "<h3>No results. Please select taxation period.</h3><hr>";
return;
} else {
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
} else {
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("display_taxation_data").innerHTML = xmlhttp.responseText;
}
};
xmlhttp.open("GET","accounting_get_period_data_labour.php?period="+str,true);
xmlhttp.send();
}
}
Code for accounting_get_period_data_labour.php ( set of records being generated based on previously selected time frame.)
echo "<tr id='record-$id'>";
echo "<td width='40'><a href='accounting_expenses_delete.php?delete=$id' class='delete'><i class='fa fa-times fa-2x' aria-hidden='true' title='Delete'></i></a></td>";
echo '</tr>';
And delete function that I want to trigger once button DELETE
is pressed:
$(function() {
$('a.delete').click(function(e) {
e.preventDefault();
var parent = $(this).parent("td").parent("tr");
console.log('idno : ' + parent);
$.ajax({
type: 'post',
url: 'accounting_expenses_delete.php',
data: 'delete=' + parent.attr('id').replace('record-',''),
beforeSend: function() {
parent.animate({'backgroundColor':'#fb6c6c'},100);
},
success: function() {
parent.fadeOut(100,function() {
parent.remove();
});
}
});
});
});
And finally short code for accounting_expenses_delete.php
<?
include "connectdb_mysqli.php";
$testdel = $_POST['delete'];
$result = $mysqli->query("DELETE FROM `test` WHERE id='$testdel'");
?>
Please let me know if you need some more information.
Looking forward to your advice or solution on how I can achieve that DELETE
action. Thank you