doufeng1249 2016-01-15 17:14
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如何将sql结果分成不同的html列

I have a table:

| s_id | s_date     | s_movie               | s_hour | s_price |
|    1 | 2015-11-11 | The lord of the rings |  11:00 |       5 |
|    2 | 2015-11-11 | The lord of the rings |  11:00 |       4 |
|    3 | 2015-11-11 | The lord of the rings |  11:00 |       4 |
|    4 | 2015-11-11 | Harry Potter          |  12:00 |       5 |
|    5 | 2015-11-11 | Harry Potter          |  12:00 |      13 |
|    6 | 2015-11-11 | Harry Potter          |  12:00 |      13 |
|    7 | 2015-11-11 | Harry Potter          |  12:00 |       5 |

And result:

$result = mysql_query("
    SELECT *
     , count(s_price) as uniq_p 
     , SUM(s_price) as uniq_all 
    from table 
    group 
    by s_movie
     , s_price 
    order 
    by s_movie desc
");

HTML table display:

+------------+------------+--------+-----+
| Date       | Movie      | Price  | Sum |
+------------+------------+--------+-----+
| 2015-11-11 | The lord.. | 2 x 4  |   8 |
| 2015-11-11 | The lord.. | 1 x 5  |   5 |
| 2015-11-11 | Harry..    | 2 x 5  |  10 |
| 2015-11-11 | Harry..    | 2 x 13 |  26 |

How to join results like this?

+------------+-------------+---------+---------+-----+    
| Date       | Movie       | Price_1 | Price_2 | Sum |
+------------+-------------+---------+---------+-----+  
| 2015-11-11 | The lord..  |  1 x 5  |  2 x 4  |  13 |
| 2015-11-11 | Harry..     |  2 x 13 |  2 x 5  |  36 |

Here is a msql example: http://sqlfiddle.com/#!2/2c0f4/2

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  • 普通网友 2016-01-15 17:35
    关注

    Naturally you can do it all in php and it's probably the best way to go about it.

    Now if you still want to do the most of it in the database you can do this

    UPDATED:

    SELECT s_date, s_movie, 
           GROUP_CONCAT(CONCAT(price_count, ' x ', s_price) ORDER BY s_price DESC) prices, 
           SUM(s_price * price_count) price_sum
      FROM
    (
      SELECT s_date, s_movie, s_price, COUNT(*) price_count, SUM(s_price) price_sum
        FROM table1
       GROUP BY s_date, s_movie, s_price
    ) q
     GROUP BY s_date, s_movie DESC
    

    Which will give you the following:

    +---------------------+-----------------------+--------------+-----------+
    | s_date              | s_movie               | prices       | price_sum |
    +---------------------+-----------------------+--------------+-----------+
    | 2015-11-11 00:00:00 | The lord of the rings | 1 x 5,2 x 4  |        13 |
    | 2015-11-11 00:00:00 | Harry Potter          | 2 x 13,2 x 5 |        36 |
    +---------------------+-----------------------+--------------+-----------+
    

    Here is SQL Fiddle demo

    Now you can explode() prices column value by , while you're iterating over the resultset.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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