解析错误：语法错误，意外'if'（T_IF），期待'，'或';' [关闭]

Question

Code PHP

    <p>'
 if($Show['Name6'] != NULL) {
 echo '<p><b>Name: </b>'.$Show["Name6"].' &nbsp;&nbsp; <b> Post : </b>'.$Show["Post6"];
 }'</p>

   </div>';
  }     
  ?>

I need help To correct this error

Answer 1

Use like.

 <?php
 echo '<p>';
 if($Show['Name6'] != NULL) {
 echo '<p><b>Name: </b>'.$Show["Name6"].' &nbsp;&nbsp; <b> Post : </b>'.$Show["Post6"];
 }
  echo'</p></div>';
  }     
 ?>