从mysql查询中选择单行并将其保存到变量

Question

How can I select a row from mysql query and save it to variable. This is the full code I am currently using:

    <?php
    header('Content-Type: text/html; charset=utf-8');
    include 'config.php';

    // Connect to server and select databse.
    mysql_connect("$dbhost", "$dbuser", "$dbpass")or die("cannot connect");
    mysql_select_db("$dbname")or die("cannot select DB");


    $IND=$_POST['id'];


    $IND = stripslashes($IND);
    $IND = mysql_real_escape_string($IND);

    $sql = "select * from table where IND='$IND'";
    $result=mysql_query($sql);

       $row = mysql_fetch_array($result);
      $number = $row['number'];


    // Mysql_num_row is counting table row
    $count=mysql_num_rows($result);

    if ($count == 1) {
       $message = mysql_fetch_assoc($result);
        $message['status'] = 'ok';
        $message = array($message);


    } else {
         $message = mysql_fetch_assoc($result);
        $message['status'] = 'error';
        $message = array($message);
    }


    header('Content-Type: application/json');
        print '{"key":'. json_encode($message) .'}';
?>

But when I use $row = mysql_fetch_array($result); $number = $row['number']; the JSON encoded $message is shown undefined.

So how can I select a single record from mysql query and make all the rest of my code to work also?

Answer 1

declare the variable $message as array and then assign the values in the if condition . Try as follows :

$message=array();
$count=mysql_num_rows($result);

    if ($count == 1) {
       $message = mysql_fetch_assoc($result);
        $message['status'] = 'ok';
        $message = array($message);


    } else {
         $message = mysql_fetch_assoc($result);
        $message['status'] = 'error';
        $message = array($message);
    }