doujingxi3356 2016-04-11 16:04
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将多维Javascript数组保存到服务器端CSV

I'm trying to save a multidimensional Javascript array as a CSV file on the server. So far, my code creates the CSV file, but the file doesn't contain my array, and I'm not sure why.

(where outputData is established)

function dataSave(){
outputStr = JSON.stringify(outputData);
$.ajax({
    type: "POST",
    url: "csvout.php",
    data: outputStr,
    dataType: 'html',
});}

csvout.php:

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">

<?php    
$array = json_decode($_POST['outputStr']);
$file = fopen("out/data.csv","w");
foreach ($array as $line){
    foreach ($line as $item){
        fputcsv($file,explode(',',$item));
        }
    }

fclose($file); 
?>

</head>
<body>
</body>
</html>

The data is an array of arrays like this one-- it's data obtained from the client, who is participating in a scientific experiment. Everything is a string.

0: "tuba.mp3"
1: "prac"
2: "1"
3: "0"
4: "type1"
5. "500"

0: "clap.mp3"
1: "main"
2: "0"
3: "0"
4: "type1"
5. "300"

[...]
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1条回答 默认 最新

  • doubu1853 2016-04-11 16:28
    关注

    You are passing a raw JSON string as your query parameter but are attempting to access it as a named parameter. Updated code:

    function dataSave(){
    outputStr = JSON.stringify(outputData);
    $.ajax({
        type: "POST",
        url: "csvout.php",
        data: { outputStr: outputStr },
        dataType: 'html',
    });}
    
    
    <!DOCTYPE html>
    <html>
    <head>
    <meta charset="UTF-8">
    
    <?php    
    $array = json_decode($_POST['outputStr']);
    adding var_dump($array); here produces NULL
    
    $file = fopen("out/data.csv","w");
    foreach ($array as $line){
        fputcsv($file,$item);
    }
    
    fclose($file); 
    ?>
    
    </head>
    <body>
    </body>
    </html>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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