PHP - 只能通过引用传递变量

Question

$v1['ip'] = $url;

.

why isn´t the following working ?

$sock = @stream_socket_client('tcp://'.$v1['ip'].':25565'. $errno, $errstr, 1);

but this:

$sock = @stream_socket_client('tcp://'.$v1['ip'].':25565'. $errno, $errstr);

and this:

$sock = @stream_socket_client('tcp://'.$url.':'.$port, $errno, $errstr, 1);

what is the default timeout ?

Answer 1

In your first example, you're concatenating the remote socket with the error number, so $errstr is actually the error number, and 1 is the error string. PHP can't assign to 1, so the call fails.

To find the default timeout, have a look at the docs for stream_socket_client(). In the function signature, you can see the $timeout parameter defaults to the float returned by ini_get("default_socket_timeout"), so all you have to do is echo that or look in your PHP config, and you have the default timeout.