douzhuo1853 2017-01-04 05:42
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将Java方法Base64.encodeToString()转换为PHP

Hello I have the below java code:

Base64.encodeToString(("users name").getBytes(), 2);

And I'm trying to convert it to php:

bytesEnc("users name");

function bytesEnc($string) {
    $bytes = array();
    for($i = 0; $i < strlen($string); $i++){
        $bytes[] = ord($string[$i]);
    }
    return $bytes;
}

I converted getBytes() but I don't know what to do next. I know function base64_encode exists inn PHP but the second argument of encodetoString java method with value 2 bothers me. Please, help.

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  • dongshou2017 2017-01-04 06:08
    关注

    According to the docs the second parameter is a bitwise flag.

    If the value is 2, then the flag NO_WRAP is used:

    Encoder flag bit to omit all line terminators (i.e., the output will be on one long line).

    This means its removes the new lines.

    function bytesEnc($string){
      $string = str_replace(PHP_EOL, '', $string);
    
      $bytes = array();
      for($i = 0; $i < strlen($string) - 1; $i++){
        $bytes[] = ord($string[$i]);
      }
      return $bytes;
    }
    
    echo base64_encode(implode('',bytesEnc('users name')));
    
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