<script type="text/javascript">
function OnSliderChanged (slider) {
var sliderValue = document.getElementById (slider.id + "Value");
sliderValue.innerHTML = slider.value;
}
function Init () {
var slider = document.getElementById ("slider1");
OnSliderChanged (slider);
var slider = document.getElementById ("slider2");
OnSliderChanged (slider);
}
</script>
0<input type="range" id="slider1" min="0" max="100" step="1" style=width:50% onchange="OnSliderChanged (this)" />100
<span id="slider1Value" class="sliderValue"></span>
<br /><br /><br />
0<input type="range" id="slider2" min="0" max="100" step="1" style=width:50% onchange="OnSliderChanged (this)" />100
<span id="slider2Value" class="sliderValue"></span>
<br>
<input type="submit" onmouseover="this.style.cursor=\'pointer\';" OnMouseOut="this.style.cursor=\'default\';">
<?php
if (isset($_GET['value=20'&&'value1=40']))
{
$username = 'root';
$password = '';
$hostname = 'localhost';
$dataname = mysql_connect($hostname,$username,$password) or die("Connection failed: ");
$selected = mysql_select_db('testdb',$dataname) or die("Could not select table1");
$result = mysql_query("SELECT * FROM `table1`");
$last = '';
echo "<table>
<tr>
<th>id</th>
<th>name</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo"<tr>
<td>".$row['0']."</th>
<td>".$row['1']."</td>
</tr>";
}
mysql_close($dataname);
}
else
{
echo " No Values Found";
}
?>
I am trying to get the input values into the php which should show the table.But am not getting the table as result am getting "No values Found" in the initial page itself. Am new to this php n javascript.. For eg i need to get the table when values 20 n 40 entered as input...Can someone please help me..?