PHP如果Else始终显示ELSE并打印变量

Question

I have a plugin that let's me get custom fields. The theme I'm working is for a magazine, and some writers have twitter accounts and some don't.

I want to show a different box in each of those cases.

Here's my code:

    <?php
    $twit = the_field('twitter'); 
    ?>

    <?php 
        if (!empty($twit)) { 
    ?>

                     <p> <?php the_field( 'autor' ); ?>  |  <a href="https://twitter.com/<?php echo rawurlencode ( the_field( 'twitter' )); ?>" class="twitter-follow-button" data-show-count="false" data-lang="es" data-dnt="true">Seguir a @<?php echo rawurlencode ( the_field( 'twitter' )); ?></a>
<script>!function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0],p=/^http:/.test(d.location)?'http':'https';if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src=p+'://platform.twitter.com/widgets.js';fjs.parentNode.insertBefore(js,fjs);}}(document, 'script', 'twitter-wjs');</script>  |  <?php the_field( 'fotos' ); ?>  |</p>

    <?php } else { ?>

           <p>Nothing to see here</p>

    <?php } ?>

The "nothing to see here" paragraph is just to test, the idea is to get the info from autor and fotos and create a different sentence.

My problem with this code is that in any case, I get the Nothing to see here message, and if the twit field exists, it gets printed, and from trial and error, it looks that it gets printed from when I create the variable $twit.

Answer 1

You're using the wrong function.

the_field will echo out the content of that field, without returning anything. If you want it to return a value, you need to use get_field instead.

Try:

$twit = get_field('twitter'); 

WordPress has a lot of functions that have fairly similar names, and it's worth a little time reading the documentation. As a rule, functions that return a value always start with get_.