douyi2798 2017-06-27 03:38
浏览 207
已采纳

列数与第1行的值计数不匹配,任何建议[关闭]

I'm getting an error using PHP and MySQL for inserting a query from a form into a databse. The error is

Column count doesn't match value count at row 1

$sql = "INSERT INTO Jobs (
    JobSubject,
    JobCompany,
    JobSalary,
    JobLocation,
    JobDate,
    JobCat,
    JobPostBy
) VALUES (
    '" . mysql_real_escape_string($_POST['JobSubject']) . "',
    " . mysql_real_escape_string($_POST['JobCompany']) .",
    " . mysql_real_escape_string($_POST['JobSalary']) .",
    " . mysql_real_escape_string($_POST['JobLocation']) .",
    NOW(),
    " . mysql_real_escape_string($_POST['JobCat']) . ",
    " . $_SESSION['userId'] . "
)";
  • 写回答

1条回答 默认 最新

  • douyi1963 2017-06-27 03:46
    关注

    You are missing some single quotes.

    Here's the correct syntax:

    $sql = "
        INSERT INTO Jobs (
            JobSubject,
            JobCompany,
            JobSalary,
            JobLocation,
            JobDate,
            JobCat,
            JobPostBy
        )
        VALUES(
            '" . mysql_real_escape_string($_POST['JobSubject']) . "',
            '" . mysql_real_escape_string($_POST['JobCompany']) . "',
            '" . mysql_real_escape_string($_POST['JobSalary']) . "',
            '" . mysql_real_escape_string($_POST['JobLocation']) . "',
            NOW(),
            '" . mysql_real_escape_string($_POST['JobCat']) . "',
            '" . $_SESSION['userId'] . "'
        )
    ";
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
编辑
预览

报告相同问题?

手机看
程序员都在用的中文IT技术交流社区

程序员都在用的中文IT技术交流社区

专业的中文 IT 技术社区,与千万技术人共成长

专业的中文 IT 技术社区,与千万技术人共成长

关注【CSDN】视频号,行业资讯、技术分享精彩不断,直播好礼送不停!

关注【CSDN】视频号,行业资讯、技术分享精彩不断,直播好礼送不停!

客服 返回
顶部