drnmslpz42661 2011-12-07 18:10
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基于字符串前缀优化子数组的创建

In my last question, was created a way to divide a array based in the string pattern Father_son, but now i need a way to split too a new pattern: Father_N_son

Original (generated by http://ideone.com/pmHHR code) :

array
  'Pagamento' => 
    array
      'data' => string '' (length=0)
      '0_pessoaId' => string '85' (length=2)
      '0_valorBruto' => string '890.00' (length=6)
      '1_pessoaId' => string '83' (length=2)
      '1_valorBruto' => string '20.00' (length=5)

Now i need:

array
  'Pagamento' => 
    array
      'data' => string '' (length=0)
      0 => 
        array
          'pessoaId' => string '85' (length=2)
          'valorBruto' => string '890.00' (length=6)
      1 => 
        array
          'pessoaId' => string '83' (length=2)
          'valorBruto' => string '20.00' (length=5)

Thanks, Celso

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  • douan4347 2011-12-08 19:58
    关注

    my solution with regex:

    static function parserRequest($array = null) {
    
            if (empty($array)) {
                $array = $_REQUEST;
            }
    
            foreach ($array as $k => $v) {
    
                $name = explode('_', $k);
                $newkey = array_shift($name);
                $newname = implode('_', $name);
    
                //para o padrão Entidade.n.atributo
                if(preg_match("/[0-9]_[a-z]/", strtolower($newname))){
    
                    $nameValued    = explode('_',$newname);
                    $newkeyValued  = array_shift($name);
                    $newnameValue  = implode('_', $name);
    
                    $result[$newkey][$newkeyValued][$newnameValue] = $v;
    
                }else{
    
                    //para o padrão Entidade.atributo
                    $result[$newkey][$newname] = $v;
    
                }
    
            }
    
            return $result;
        }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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