dsxi70423 2013-12-31 12:39
浏览 44
已采纳

将AJAX查询结果的每个值存储到Javascript变量

Here's a jQuery-ajax function that returns some data from a php file.

$('.up').click(function() {
    var act = $('.active').val();

    $.ajax({
        type: "POST",
        url: "database.php",
        data: {
            value: act
        }
    }).done(function(result) {
        $('#msg').html(result)
    });
});

I get the array result of the query. I have no problem with.

PHP Result :

array(2) {
  [0]=> array(2) { ["Label"]=> string(3) "Group1" ["Count"]=> string(1) "244" }
  [1]=> array(2) { ["Status"]=> string(7) "Group2" ["Count"]=> string(1) "125" }
}

Actual query result is this.

Label   Count
Group1  244
Group2  125

Now that I get the result. I wanted to store the numbers of the Count column to two different javascript variables.

So far I tried with this.

var value1 = "<?php echo htmlentities($data[0]['Count']) ?>";
var value2 = "<?php echo htmlentities($data[1]['Count']) ?>";

Tried replacing with the above piece of code with result in the ajax call.

But when I did this the click event itself was not triggered.

I've saved the numbers to two php variables namely value1 and value2.

And in the result of the ajax call i get the result like 244125.

Help me saving that number to two different javascript variables.

  • 写回答

1条回答 默认 最新

  • doule6314 2013-12-31 14:00
    关注

    I am assuming you are going to do something with this data so you'll need to know what you are looking for.

    Get your PHP to serve up JSON with keys like so:

    {"Bob": "24", "Sue": "12"}
    

    This way you can access the information you need or just loop through the whole lot. I've made a little fiddle which I am hoping will help you understand.

    Ultimately you simply want to use the jQuery $.getJSON to pull the information and then deal with it however you please.

    http://jsfiddle.net/PgVkL/

    If you need PHP to output in the format you specified then you can do:

    $people = array("24", "12", "16", "48");
    var_dump(json_encode($people));
    

    Here's the docs: http://uk3.php.net/json_encode

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 metadata提取的PDF元数据,如何转换为一个Excel
  • ¥15 关于arduino编程toCharArray()函数的使用
  • ¥100 vc++混合CEF采用CLR方式编译报错
  • ¥15 coze 的插件输入飞书多维表格 app_token 后一直显示错误,如何解决?
  • ¥15 vite+vue3+plyr播放本地public文件夹下视频无法加载
  • ¥15 c#逐行读取txt文本,但是每一行里面数据之间空格数量不同
  • ¥50 如何openEuler 22.03上安装配置drbd
  • ¥20 ING91680C BLE5.3 芯片怎么实现串口收发数据
  • ¥15 无线连接树莓派,无法执行update,如何解决?(相关搜索:软件下载)
  • ¥15 Windows11, backspace, enter, space键失灵