duange051858 2013-03-07 02:13
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PHP未定义变量,但脚本工作正常,如果我定义变量它不起作用[关闭]

I have a problem with an undefined variable, if I define the variable the script does not work correctly, I know it's a simple answer I just can't find it.

Here is my code: ( I use this in a for each loop )

$weight= ($item['weight']*$item['quantity']);  
$totalweight = ($totalweight + $weight) 

echo $totalweight;

The script works perfect and gives me the correct answerexcept I get an undefined variable error on line 2 $totalweight

I have tried to set the variable it then breaks the calculation.

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2条回答 默认 最新

  • dongwei1954 2013-03-07 02:20
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    You need to initialize the variable outside of the loop so it's not overwritten on every iteration:

    $totalweight = 0;
    foreach ($items as $item) {
        $weight= ($item['weight']*$item['quantity']);  
        $totalweight = ($totalweight + $weight) 
    }
    
    echo $totalweight;
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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