I am retrieving my date like this in my php query:
DATE_FORMAT(items.r_date, '%M %D, %Y') as r_date
And then displaying it like this, for example:
January 1st, 1934
However, if the year is 1111, I would like to make the date say something custom.
Such as (I know this isn't real code, just trying to explain what I want to do:
if ($row['r_date'] CONTAINS '*1111*') { $r_date = "my custom message"; } else $r_date = $row['r_date'];
Could anyone help me solve this?
Thank you for your time.
我在我的php查询中检索我的日期：
< 代码> DATE_FORMAT（items.r_date，'％M％D，％Y'）为r_date然后像这样显示它，例如：
1934年1月1日但是，如果年份是1111年，我想让日期说出定制的东西 。
例如（我知道这不是真正的代码，只是试图解释我想要做什么：
if（ $ row ['r_date'] CONTAINS'* 1111 *'）{$ r_date =“我的自定义消息”;}否则$ r_date = $ row ['r_date']; \ n有人可以帮我解决这个问题吗？
感谢您的时间。
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