sqli-lab 输入?id=1'时,sql语句自动添加\


本人小白但根据资料注入http://localhost/sqlilabs/Less-1/?id=1' 时数据库应该查不到数据啊???SELECT * FROM users WHERE id='1'',但是浏览器里却没有报错?传到数据库里变成这个查询了SELECT * FROM users WHERE id='1\'' LIMIT 0,1?求大神解答。后面的练习也都是这样,没法往下做。

巴拉巴大魔 经过探索这是PHP版本的问题我phpstudy默认使用的5.2.17,后来我换成了5.3.29 就没有这个情况了
8 个月之前 回复




巴拉巴大魔 这是sql注入的练习,应该是加了 ' 就得不到数据,但是这个版本的php不知道为什么自动给转义了,换一个php版本就正常了
8 个月之前 回复
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You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '\' LIMIT 0,1' at line 1


![图片说明](https://img-ask.csdn.net/upload/201902/18/1550474270_212924.png) 如图片,本人小白一只百度一番无果只能求助各位大佬们了! 感谢各位大神们的解答!


在搭建phpstudy v8.0 + sqli-labs时,出现下面这个问题 ![图片说明](https://img-ask.csdn.net/upload/201910/11/1570781041_68591.png) 本人小白一只,百度一番无果只能求助各位大佬们了!感谢各位大神们的解答!

搭建SQL注入平台 sqli-labs

系统 win10 服务器环境 phpstudy 希望预装 sqli-labs ![图片说明](https://img-ask.csdn.net/upload/202001/11/1578732546_915724.png) sqli-labs 安装包路径 https://github.com/Rinkish/Sqli_Edited_Version 求大神解决 要是换版本 换安装包 但本人傻乎乎的 还请写的详细些


能进这里 ![图片说明](https://img-ask.csdn.net/upload/201912/12/1576142598_239767.png) ![图片说明](https://img-ask.csdn.net/upload/201912/12/1576142638_600283.png) 但是点进去后就成这样了 ![图片说明](https://img-ask.csdn.net/upload/201912/12/1576142718_536906.png) 想问一下大佬们,怎么解决?

(初学萌新)sqli-labs点击Setup/reset Database for labs出错,为什么?

个人认为是数据库出了错,但是不清楚错在哪里 ![图片说明](https://img-ask.csdn.net/upload/201909/24/1569289769_923515.png)![图片说明](https://img-ask.csdn.net/upload/201909/24/1569289791_696359.png)

You don't have permission

想玩下这个sqli labs注入实验室:https://github.com/Audi-1/sqli-labs (我是windows xp+apache+php+mysql的) 按照说明将文件解压到web根文件夹,可以进入http://localhost/sqli-labs/index.html,但是点相应的less-1时就出现了 403 Forbidden You don't have permission to access /sqli-labs/Less-1/ on this server. 如果访问http://localhost/sqli-labs/Less-1/index.php也是可以顺利访问的。 请问怎么解决?谢谢


在学习dvwa中的sql注入时,教程中有条语句http://localhost/DVWA-1.0.8/vulnerabilities/sqli/?id=1' and length(char(113,114))=2+--+ &Submit=Submit#。该句中的+--+的意思和作用?把它去掉之后,注入会失败,去掉两个+后,注释符号--失效。请大神来解答一下!!!


<div class="post-text" itemprop="text"> <p>this is my first time using Mysqli and i been stuck on this problem for about an hour now. I am getting this error</p> <pre><code>mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement in C:\wamp\www\WebContent\success.php on line 30 </code></pre> <p>i have counted like 10 times the questions marks in the prepare statement and there are 21, then i counted the s and the variables in bind_param and there are 21 too. I am new at Mysqli, I was wondering if i can get any suggestion on how to aproach and debug this problem, thank you for all your help</p> <pre><code>&lt;?php $mysqli = new mysqli("localhost", "root","","test"); if (mysqli_connect_errno()) { printf("Connect failed: %s ", mysqli_connect_error()); exit(); } $i=0; if ($stmt = $mysqli-&gt;prepare("UPDATE `table` SET `Lan_ID` = '?', `Switching` = '?', `Own` = '?',`Division` = '?',`Switch_Number` = '?', `Telecom_Circuit_number` = '?', `Transmitter_Frequency` = '?', `Receiver_Frequency` = '?', `Band_width` = '?', `Channel` = '?', `Equipment` = '?', `Power` = '?', `Line_designation` = '?', `Voltage` = '?', `Phase` = '?', `Modulate` = '?', `Terms` = '?', `Trap` = '?', `Ltunner` = '?', `Link` = '?', `Comment` = '?' ". $_GET['where'.$i] )) { $stmt-&gt;bind_param('sssssssssssssssssssss', $_GET[$i.'LanID'],$_GET[$i.'Switching'], $_GET[$i.'Own'], $_GET[$i.'Division'], $_GET[$i.'Switch_Number'], $_GET[$i.'Telecom_Circuit_number'], $_GET[$i.'Trasmitter_frq'], $_GET[$i.'Receiver_frq'], $_GET[$i.'Band_width'], $_GET[$i.'Channel'], $_GET[$i.'Equipment'], $_GET[$i.'Power'], $_GET[$i.'Line_designation'],$_GET[$i.'Voltage'], $_GET[$i.'Phase'],$_GET[$i.'Modulate'],$_GET[$i.'Terms'], $_GET[$i.'Trap'],$_GET[$i.'Ltunner'], $_GET[$i.'Link'], $_GET[$i.'Comment'] );//this is line 30 btw } else { printf("Prepared Statement Error: %s ", $mysqli-&gt;error); } $stmt-&gt;close(); ?&gt; </code></pre> </div>


<div class="post-text" itemprop="text"> <p>Looks simple but I unable to make it happen. When browsing <code>domain.com/post/1</code>, it should show data from row <code>id</code> which value <code>1</code>.</p> <p>Row <code>id</code> is integer (<code>int4</code>).</p> <p>Below the the codes, which is not working:</p> <pre><code>package main import "fmt" import "github.com/go-martini/martini" import "net/http" import "database/sql" import _ "github.com/lib/pq" func SetupDB() *sql.DB { db, err := sql.Open("postgres", "user=postgres password=apassword dbname=lesson4 sslmode=disable") PanicIf(err) return db } func PanicIf(err error) { if err != nil { panic(err) } } func main() { m := martini.Classic() m.Map(SetupDB()) m.Get("/post/:idnumber", func(rw http.ResponseWriter, r *http.Request, db *sql.DB) { rows, err := db.Query(`SELECT title, author, description FROM books WHERE id = params["idnumber"]`) PanicIf(err) defer rows.Close() var title, author, description string for rows.Next() { err:= rows.Scan(&amp;title, &amp;author, &amp;description) PanicIf(err) fmt.Fprintf(rw, "Title: %s Author: %s Description: %s ", title, author, description) } }) m.Run() } </code></pre> </div>


<div class="post-text" itemprop="text"> <p>I have connected to a database for the first time with oop and stright away come up with an issue, below is my code which i'm struggling with:</p> <pre><code>$q = 'SELECT * FROM test'; $sqli-&gt;query($q); if($sqli-&gt;query($q)){ echo "worked"; } if($sqli-&gt;error){ echo $sqli-&gt;error; } </code></pre> <p>I have checked for errors when connecting to the db and that works fine, but when I run this query I get no output, why? I expected an error or "worked", but have got neither.</p> <p>Whats happening?</p> </div>


<div class="post-text" itemprop="text"> <p>EDIT: Found the error. The sting replace statement was adding an extra space. Fixed now, thanks.</p> <p>I've been looking at this too long, I can't find the error.</p> <p>Here's what I've got:</p> <pre><code>echo $client_name." - ".$location; $query = mysql_query("SELECT * FROM spc_clients WHERE (client_name='".$client_name."' AND location='".$location."')") or die(mysql_error()); while ($results = mysql_fetch_array($query)) { // Other code... } </code></pre> <p>When I echo, I get 'Client1' and 'Location1". When I put the SQL query into PHPMyAdmin, and replace those values, the query runs fine and brings up results. On the page it's on, I get nothing.</p> <p>I have no syntax errors, and the mysql_error isn't coming back with anything either.</p> <p>What am I missing?</p> </div>

SQL语句不起作用,我做错了什么> [重复]

<div class="post-text" itemprop="text"> <div class="question-status question-originals-of-duplicate"> <p>This question already has an answer here:</p> <ul> <li> <a href="/questions/11321491/when-to-use-single-quotes-double-quotes-and-backticks-in-mysql" dir="ltr">When to use single quotes, double quotes, and backticks in MySQL</a> <span class="question-originals-answer-count"> 12 answers </span> </li> </ul> </div> <p>I'm creating an admin panel with a form that creates a blog post. When I try to insert this into the database, I'm getting an error. This is my SQL statement:</p> <pre><code>INSERT INTO blog_posts ('title', 'author', 'tags', 'category', 'body') VALUES ('$title', '$author', '$tags', '$category', '$body'); </code></pre> <p>What am I doing wrong? Full code:</p> <pre><code>$servername = "host"; $username = "username"; $password = "password"; $dbname = "dbname"; // Create connection $conn = mysqli_connect($servername, $username, $password, $dbname); // Check connection if (!$conn) { die("Connection failed: " . mysqli_connect_error()); } $title = $_POST['title']; $author = $_POST['author']; $tags = $_POST['tags']; $category = $_POST['category']; $body = $_POST['editor1']; // sql to insert a record $sql = "INSERT INTO blog_posts ('title', 'author', 'tags', 'category', 'body') VALUES ('$title', '$author', '$tags', '$category', '$body');"; if (mysqli_query($conn, $sql)) { echo "Succes"; } else { echo "Error"; } mysqli_close($conn); </code></pre> <p>So, what do I do now?</p> </div>

SQL注入保护 - 单引号[重复]

<div class="post-text" itemprop="text"> <blockquote> <p><strong>Possible Duplicate:</strong><br> <a href="https://stackoverflow.com/questions/60174/best-way-to-prevent-sql-injection-in-php">Best way to prevent SQL injection in PHP?</a> </p> </blockquote> <p>Ive been doing a bit of testing to protect my sites from SQL Injection. I see there are a couple of ways of doing so, Escaping my user inputs, adding slashes, or better yet using parameterized sql statements.</p> <p>I had this test code..</p> <pre><code>$q=$_GET["q"]; $game = mysql_query("SELECT * FROM `Games` WHERE `id` = '$q'"); $game = mysql_fetch_array($game); echo "&lt;h4&gt;ID: ".$game[0]."&lt;br /&gt;&lt;/h4&gt;name: " . $game[1]; </code></pre> <p>And I tried several SQLi requests and could not get my test page to error, or show any extra data.</p> <p>But when i changed my sql statement code to this (Removed the single quotes around $q)..</p> <pre><code>$game = mysql_query("SELECT * FROM `Games` WHERE `id` = $q"); </code></pre> <p>I could perform simple SQLi's and get some results.</p> <p>So is just wrapping my user inputs in single quotes good enough? Or have i over looked more complex SQLi techniques?</p> </div>

如何在使用SQLi的SQL IN运算符的Prepared语句中使用php数组? [重复]

<div class="post-text" itemprop="text"> <div class="question-status question-originals-of-duplicate"> <p>This question already has an answer here:</p> <ul> <li> <a href="/questions/920353/can-i-bind-an-array-to-an-in-condition" dir="ltr">Can I bind an array to an IN() condition?</a> <span class="question-originals-answer-count"> 21 answers </span> </li> </ul> </div> <p>This is my code: </p> <blockquote> <pre><code>if(isset($_POST['abc'])) { $things['abc'] = mysqli_real_escape_string($connect, implode("','", $_POST['abc'])); $result = mysqli_query($connect, "SELECT * FROM this_list WHERE abc_column IN ('{$things['abc']}')"); if (!$result) { echo "Error fetching results: " . mysqli_error(); } else { while ($row = mysqli_fetch_array($result)) { $abc[] = $row['description']; } } } </code></pre> </blockquote> <p>The above code uses mysqli_real_escape_string(), and <code>$things</code> is an array with checkbox values that is received via POST. This array contains the list of strings separated by comma that I am using in the query. </p> <p>When I was searching on the net, I noticed that some people say <code>mysqli_real_escape_string()</code> may prevent sql injection, I was thinking maybe prepared statement for checkbox values might be more safer against sql injection.</p> <p>I have used prepared statement with separate parameters to prevent sql injection. But I am stuck on this one and I dont know how to change the above code to a prepare() statement since it uses an array <code>$things['abc']</code>. I tried searching and everytime I search array in prepared statement, I am getting info on Java, etc.. Can someone enlighten me on how I can do this with php please?</p> <p><strong>EDIT:</strong></p> <p>After the help from onetrickpony code below, this is what I have now:</p> <pre><code>if(isset($_POST['abc'])) { $ph = rtrim(str_repeat('?,', count($_POST['abc'])), ','); $query = sprintf("SELECT col1 FROM abc_table WHERE col2 IN (%s)", $ph); $stmt = mysqli_prepare($connect, $query); // bind variables $params = array(); foreach($_POST['abc'] as $v) $params[] = &amp;$v; array_unshift($params, $stmt, str_repeat('s', count($_POST['abc']))); // s = string type call_user_func_array('mysqli_stmt_bind_param', $params); mysqli_stmt_execute($stmt); // Get the data result from the query. mysqli_stmt_bind_result($stmt, $col1); /* fetch values and store them to each variables */ while (mysqli_stmt_fetch($stmt)) { $name[] = $col1; echo $name; } //loop to echo and see whats stored in the array above foreach($name as $v) { echo $v; } // Close the prepared statement. $stmt-&gt;close(); } </code></pre> <p>In the above code, the sqli method for prepare statement seems to work which is great. However, when I use the mysqli_stmt_bind_result(), the $name[] array inside the while loop only seems to print the last row.</p> <p><strong>UPDATE:</strong></p> <p>onetrickpony's code with the mysqli method for using php array in a Prepared Statement worked fine and it was a very good approach he had suggested. However, I have been having nightmare with the second half of the code which is trying to get the fetched array results to work. After trying for more than a day, I have given up on that and I have made the switch to PDO. Again onetrickpony's advise below was totally worth it. Making the switch to PDO made the code so much easier and simpler and couldnt believe it.</p> </div>


<div class="post-text" itemprop="text"> <p><strong>Problem:</strong></p> <p>Unable to store data with mySQL stored procedure with <code>mysqli_begin_transaction</code>.</p> <p><strong>Details:</strong></p> <p>The below code will do simple <code>insert</code> and <code>select</code> using mysql stored procedure. Code runs fine <em>without</em> <code>select</code> statement. However once the <code>select</code> statement is added, it won't commit any data even the query returns success at PHP side.</p> <p><strong>Snippets (PHP):</strong></p> <pre><code>$DB_DRRM_SQLI = mysqli_connect("localhost","root","", "sandbox_db"); mysqli_begin_transaction($DB_DRRM_SQLI); $SQL_QUERY_CODE = "CALL SANDBOX_TEST()"; $DB_QUERY = mysqli_query($DB_DRRM_SQLI, $SQL_QUERY_CODE); // ERROR REPORTING if($DB_QUERY === false) { echo mysqli_error($DB_DRRM_SQLI); mysqli_rollback($DB_DRRM_SQLI); } else { echo 'success'; mysqli_commit($DB_DRRM_SQLI); } exit; </code></pre> <p><strong>Snippets (mySQL Stored procedure):</strong></p> <pre><code>BEGIN INSERT INTO `sandbox_table` ( `SOME_STRING` ) VALUES ( 'ABCDEFGHIJKL...' ); SELECT LAST_INSERT_ID() AS INSERTED_ID, 'ABCDE...' AS OTHER_PARAMS; END </code></pre> <p><strong>Database (Table sandbox_table):</strong></p> <ol> <li>RECORD_PRIMARY_ID (<em>Int - Auto increment</em>)</li> <li>SOME_STRING (<em>Varchar - 500 length</em>)</li> </ol> <p><strong>Spec:</strong></p> <ul> <li>PHP version: 5.6.14</li> <li>10.1.8-MariaDB</li> <li>Storage Engine: <em>InnoDB</em></li> </ul> <p><strong>Notes:</strong></p> <ul> <li>If transaction is made at stored procedure works fine, but I need a PHP managed transaction to handle multiple query requests and response depending on the result of query. </li> <li>(It can be a possible last resort if there's no other solution, where I need to convert whole PHP code to stored procedure and need pass tons of parameter)</li> </ul> <p><strong>Methods Tested:</strong></p> <ul> <li>Tried with other PHP version 7.0.9 with same result (10.1.16-MariaDB)</li> <li>Tested with new database with no other data except <code>sandbox_table</code>and above stored procedure.</li> <li>Tested without additional include libraries (tested with purely on above snippets).</li> </ul> </div>


下面username后面的怎么解释,相当于什么sql语句 update user_info set password='1234' where username= ' ' or 1=1 or '1'='1 '

将sql转换为sqli pull id并使用php插入表中

<div class="post-text" itemprop="text"> <p>I've been searching and trying for the last few hours with no luck. Trying to do this. I have a web Purchase order system. It uses mysql which is obviously outdated. It's a simple code, I pull the ID of the last ponumber, +1 to it, and reinsert it. I also display the new number on the form. This allows my system to display the PO number before submitting, and ensures noone else gets the same number twice. Here is my old code. There is a connection section in the header, but it's the same as the conn below which is all i havent added. </p><pre><code>$row = mysql_fetch_array($result); $ID = $row['ID'] +1 ; ?&gt; &lt;?php $con = mysql_connect("localhost","username","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("purchaseorder", $con); $sql="INSERT INTO ponumber (ID) VALUES ('$ID')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } ?&gt; &lt;form action="submit.php" method="post" name="form" id="form" accept- charset="utf-8"&gt; &lt;div class="form-all"&gt; &lt;ul class="form-section"&gt; &lt;li id="cid_1" class="form-input-wide"&gt; &lt;div class="form-header-group"&gt; &lt;h2 id="header_1" class="form-collapse-table"&gt; Jillian Builders Purchase Order #:&lt;/h2&gt;&lt;center&gt;&lt;font size="9"&gt; &lt;?php echo $ID ?&gt; &lt;/h1&gt;&lt;/center&gt;&lt;/font&gt;&lt;/div&gt; </code></pre> <p>This works just fine, other than an annoying sql is deprecated warning, which im trying to change. I cannot for the life of me figure out how to get the ID number using mysqli. I have tried numerous ways with fetch assoc, with array's, but for some reason I can't make it work. Im sure there is a better way to do this than what im doing. I'm open to suggestions. In the form. The employee needs to give the PO number to a vendor. Once he pushes submit on the form it submits the number in. So i need the number before he submits the data to the database so he can give it. Which is why i used +1. I get the old ID +1 to it to show the number in the FORM ONLY. It's not relevant to the actual DB. When he submits the PO it submits the number into it, and everything lines up. All i need to do it find a way to pull the ID off. </p> <p>This is what i've tried so far to no avail</p> <pre><code>&lt;?php $data = mysqli_query($conn,"SELECT ID FROM ponumber ORDER BY ID DESC LIMIT 1"); while ($row = mysqli_fetch_assoc ($data)) { extract ($row); echo " ID=$ID +1 "; } </code></pre> <p>Hope this helps clarify where i'm at Thanks in advance. </p> </div>


<div class="post-text" itemprop="text"> <p>i wonder that both if and it's else are true.</p> <p>i got $apple_id_num from the input select form and it is a number but in string type like "7" and it is how many ids that user wants.so i convert it to integer</p> <p>now i want to check if it is not more that what i have available in my database. but statements under conditions <code>($num_rows&lt;$id_num)</code> and if <code>($num_rows&gt;=$id_num)</code> both are running.</p> <p>what i'm doin wrong?</p> <p>here is my code:</p> <pre><code>function getAppleID($apple_id_num) { $sqli=new mysqlii(); $apple_ids=$sqli-&gt;SelectFromDB($apple_id_num); $num_rows=$sqli-&gt;num_rows; $id_num=(int)$apple_id_num; if ($num_rows&gt;=$id_num){ $this-&gt;printAppleID($apple_ids,$num_rows); //$sqli-&gt;updateRows(); echo"else if running"; return $apple_id_num; } else if ($num_rows&lt;$id_num) echo "if statement was rungning"; } </code></pre> </div>


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