dts777777 2012-03-17 07:47
浏览 35

循环使用php表

i'm making a table on my website where data is pulled out of my database.

Basically what i want it to do is to check for the column where the referrer is $session and on that same row it will look for the column 'username' and it will echo the username column into the table onto the website.

What im doing is a refer a friend system but basically you can view the people you referred, so when you referred someone it would insert your name '$session' into the referrer column and now i just need it to grab that out of the database so people can see who they referred 'username' column.

Sorry for the confusing wording.

Code here

http://pastebin.com/rhYvtA2L

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2条回答 默认 最新

  • douangoo48863 2012-03-17 08:11
    关注

    lets say try this

       $my_array;
      while_loop(){
        if session == $row['Referrer']
         array_push($my_array,'your value');
    
        }
    
    评论

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