I have faced small problem regarding passing php variable outside of PHP loop. I have created table and form in same page. First table is displayed and the through edit link in form pop up dialog box appears. I want to pass dynamic ID to dialog box after click edit link. My page includes a php table and form.
PHP/HTML Table
<table>
<th>ID</th>
<th>Title</th>
<th>Edit</th>
<?php
$query="select * from video order by id desc";
$result=$con->query("SELECT * FROM video ORDER by id DESC") or die($con->error);
while($row=$result->fetch_assoc()){
$id=$row['id'];
$heading=$row['heading'];
?>
<tr>
<td>
<?php echo $id ?>
</td>
<td>
<?php echo $heading ?>
</td>
<td>
<a href="#modal2" id="pop_button">Edit</a>
</td>
</tr>
<?php } ?>
</table>
After this table, I want to display data in this form
PHP Form in dialog box
<div class="remodal" data-remodal-id="modal2" role="dialog" aria-labelledby="modal2Title" aria-describedby="modal2Desc">
<form action="" method="POST" enctype="multipart/form-data">
<table>
<tr>
<th>Video ID</th>
<td>
<input type="number" value="<?php echo $id?>" name="id" readonly></input>
</td>
</tr>
<tr>
<th>Video Title</th>
<td>
<input type="text" value="<?php echo $heading?>" name="title"></input>
</td>
</tr>
</table>
</form>
</div>
I know that while loop can't connect to popup dialog box form, so my code prints only data of first row. If I include whole code within while loop, my table structure become mess. Is there any idea to pass ID outside of while loop ? I tried using global variable method, but it doesn't work. Perhaps I can't properly use global variable. Thanks