在php中使用逆条件顺序在if else条件下使用OR

Question

I am trying to get "OK" if my condition False, i want to keep same if else order as given example, don't advice to move "else" content in "if" and "if" content in "else",

 <?php

    //Case 1 Both False
    //$point = 1001; //more than 100
    //$flag  = 1;   //flag is = 0 

    //Case 2 First False Second True
    //$point = 1000; //less than 1000
    //$flag  = 0;   //flag is = 0 

    //Case 3 First TRUE Second FALSE
    //$point = 100; //less than 100
    //$flag  = 1;   //flag is = 1 

    $point = 1001;
    $flag  = 1;   
    ?>

    <div class="box border">
    <div class="box-title">
    <?php if($flag == 0 || $point < 1000) { ?>
    <h4>Not OK</h4>
    <?php } else { ?>
    <h4>OK</h4>
    <?php }?>
    </div>

in above script //Case 1 is working but Case 2 and Case 3 both not working with OR operator

I want all 3 cases work in same pattern

Answer 1

After reading your comments:

It seems you want to show some score (in the else-branch of an if-then-else) if the user has equal/more than 1000 points or you toggle a flag (which basically means "always show points").

Normally you'd be doing that in the if-branch:

if ($flag || $point >= 1000)
{
    echo "OK";
} else {
    echo "Not OK";
}

Since you want the Not OK to be in the if-Branch you need to inverse the condition, doing so means inverting every part of the condition and the operators aswell:

• $flag becomes !$flag
• $point >= 1000 becomes $point < 1000
• || becomes &&

Result:

if (!$flag && $point < 1000)
{
    echo "Not OK";
} else {
    echo "OK";
}

Writing this into a truth-table:

flag        point       result
0           < 1000      Not OK
1           < 1000      OK
0           >=1000      OK
1           >=1000      OK