如何回显数组中的内容（例如<a href=arraydata>）

Question

I'm trying to make it where I can go to a link of off a YouTube API. (MP4), but I can't figure out how to make the link to the MP4 clickable (such as <a href=data>). I am wanting to do this for a Android project, basically just a completely online Android converter since FLVTO and onlinevideoconverter is super annoying, pops up viruses, or pops up "Your Galaxy S7 Edge is infected! install app to fix!". Here's what I've tried.

$formats = $array["streamingData"]["formats"];
    for ($a = 0; $a <= (count($formats) - 1); $a++){
        $data[] = array(
            "url" => $array["streamingData"]["formats"][$a]["url"]
            echo "<a href='"$array['streamingData']['formats'][$a]['url']"'>downloadlink</a>"

);

or

$formats = $array["streamingData"]["formats"];
    for ($a = 0; $a <= (count($formats) - 1); $a++){
        $data[] = array(
            $url => $array["streamingData"]["formats"][$a]["url"]
        );
        echo "<a href='"$url"'>adsf</a>";

Answer 1

Why still put in the array if you want to display? Just do it.

 $formats = $array["streamingData"]["formats"];
for ($a = 0; $a <= (count($formats) - 1); $a++){
   echo "<a href='".$formats[$a]['url']."'>downloadlink</a>"; 
}