dongyuan3094 2017-05-02 14:03
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当特定子字符串存在时，删除两个 之间的部分[PHP]

I have a variable in which I store some HTML code. Let's say:

<div> 
<span> test of {my_string} </span> 
{my_string} 
test of {my_string} 
</div> 
<h1> {my_string} </h1>

I would need to remove some lines containing a specific value so the end result looks like:

<div>
</div>

So I was thinking of getting the position of the string with strpos and then get the which are before and after. But how can I search backwards with strpos as I already have an offset specified?

$rep_pos = strpos($message, 'my_string');
$line_begining = ????
$line_end = strpos($message, '
', $rep_pos);

I can't use strip_tags because I don't know in advance what will be the tags around and some other strings can use the same tags.

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  • doushou8730 2017-05-02 14:13
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    You should use DOMDocument for parsing HTML tags string. Here we are using XPath query which is //*[text()=" my_string "] which means get all elements which contains my_string text.

    Try this code snippet here

    <?php

ini_set('display_errors', 1);

$string='<html>
           <body>
             <div>
               <span> my_string </span>
             </div>
             <h1> my_string </h1>
           </body>
         </html>';
$domobject= new DOMDocument();
$domobject->loadHTML($string);
$xpath= new DOMXPath($domobject);
$result=$xpath->query('//*[text()=" my_string "]');
Foreach($result as $nodes)
{
    $nodes->parentNode->removeChild($nodes);
}
echo $domobject->saveHTML();

    Solution 2:

    Regex demo

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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