添加Click函数在php中输入类型图像给出未定义的错误

Question

I am trying to make an onClick function from input type image. Here is the code

<td>
    <?php if($ring[ "bandPaths"] !='' ) echo '
<input id="bandImage" type="image" src="http://thevowapp.com/iphoneapp/vowstore/bands/'. $ring[ 'bandPaths'] . '" onClick="openGallery('.$ring[ 'bandPaths']. ');" style="width:100px; height:100px; margin-left: 10px;">
'; ?>
</td>

<script>
    function openGallery(var url) {
        $.colorbox({
            width: "80%",
            height: "80%",
            iframe: true,
            href: "/pagetoopen.html"
        });
    }
</script>

i get the error openGallery is not defined. What wrong am i doing?

Answer 1

Your Javascript syntax is invalid, you should be getting a syntax error in the console. It should be:

function openGallery(url)
{    
  $.colorbox({width:"80%", height:"80%", iframe:true, href:"/pagetoopen.html"});
}

var is only used to declare local variables in the function body. Function arguments are automatically declared as local, so the var keyword is not used there.