douye2488 2018-06-08 12:22
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在Jquery中使用php变量,作为动态创建的背景图像

I've already seen some similar posts but I think my case is different. I have the following code:

$(".imagem .bottom-buttons").on("click", ".ver-emb", function(event){
        var Image = <?php echo $row->embalagem; ?>;
//row-embalagem comes from a query search to the database.
        $(".slider-img").css("background-image", "url(../assets/imagens/<?php echo $row->embalagem; ?>)");
        $(this).addClass( "ver-prod" );
        $(this).removeClass( "ver-emb" );
        $(this).text( "Ver Produto" );
    });

I've read that you need to put the php variable into jquery variable, but how do I apply that new Jquery variable to the background-image url ?

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  • duanbeng1923 2018-06-08 12:25
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    You'd use it the same way you use any variable in JavaScript:

    "url(../assets/imagens/" + Image + ")"
    

    Additionally, if your variable is a string (you're using it as a string) then strings need to be surrounded by quotes:

    var Image = "<?php echo $row->embalagem; ?>";
    
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