在PHP中：如果找到匹配的案例，是否评估了任何剩余的案例陈述？

Question

I have a switch statement in a tight loop that looks like this:

switch(true) {
    case /*expensive comparison */:
    case /*another expensive comparison */:
    case /*different expensive comparison */:
        return true;
}
return false;

I looking to see if any of the expensive comparisons is true, but only one. I know there are other ways to accomplish this, but this one looks nice and clean. The real question is: if expensive comparison evaluates to true, does it also run another expensive comparison also, or just jump to the return?

EDIT: I realize this could be accomplished with a simple or statement, but now I want to know for theory's sake.

return /*expensive comparison */
         || /*another expensive comparison */
         || /*different expensive comparison */;

Answer 1

I finally had a chance to do some testing on this, and it looks like it (5.4 at least) stops evaluating cases once one matches. Here is how I verified that:

<?php
function evaluate($id)
{
    echo $id, "
";
    return true;
}

switch (true) {
    case evaluate(1):
    case evaluate(2):
    case evaluate(3):
    echo "Evaluated
";
}

Here is the output:

 >1
 >Evaluated