PHP获取下拉值和文本

Question

<select id="animal" name="animal">                      
<option value="0">--Select Animal--</option>
<option value="1">Cat</option>
<option value="2">Dog</option>
<option value="3">Cow</option>
</select>

if($_POST['submit'])
{
$animal=$_POST['animal'];
}

I have a dropdown like this. What I want, I want to get selected value and text in button submit using PHP. I mean if it's selected 1st one. I want to get both 1 and Cat

Please help. thank you.

Answer 1

$animals = array('--Select Animal--', 'Cat', 'Dog', 'Cow');
$selected_key = $_POST['animal'];
$selected_val = $animals[$_POST['animal']];

Use your $animals list to generate your dropdown list; you now can get the key & the value of that key.