dongyuruan2957 2013-01-11 01:41
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CodeIgniter将数据传递给视图

I am trying to pass from my controller to the view like so...

public function playerslist()
    {
        $this->load->database();
        $data = $this->db->get('skaters');
        $this->load->helper('url');
        $this->load->view('playerslist', $data);
    }

and in my view...

<?php echo $data; ?>

but I get this error...

A PHP Error was encountered

Severity: Notice

Message: Undefined variable: data

Filename: views/playerslist.php

Line Number: 76

What am I doing wrong?

What I would like to do with this data is put in a foreach statement and display everything in the $data array

foreach($data as $value => $key){
echo $key . "<br/>";
}

Thanks, J

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  • dongtangdao7232 2013-01-11 01:44
    关注

    You cannot access $data directly from your view. The $data you pass to your view has to be an associative array. The keys will then be converted to variables in your view.

    For example:

    $data = array(
        'name' => 'John',
        'bars' => 23
    );
    
    $this->load->view('playerslist', $data);
    

    Then, in your view, those will be converted to variables:

    <?php echo $name; ?> has <?php echo $bars; ?> bars of chocolate.
    

    If you want to access the data in its original format, pass that into the associative array:

    $data = $this->db->get('skaters')->result();
    $this->load->view( 'playerslist', array('data' => $data) );
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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