根据数组的数量循环遍历数组和输出链接

Question

I currently have an array as follows:

   Array ( 
    [0] => Array ( [id] => 34 [another_id] => 2805 [third_id] => 1 ) 
    [1] => Array ( [id] => 35 [another_id] => 2805 [third_id] => 1 ) 
    [2] => Array ( [id] => 36 [another_id] => 2805 [third_id] => 1 ) 
    [3] => Array ( [id] => 37 [another_id] => 2805 [third_id] => 1 ) 
    [4] => Array ( [id] => 38 [another_id] => 2805 [third_id] => 1 ) 
    [5] => Array ( [id] => 39 [another_id] => 2805 [third_id] => 1 ) 
    [6] => Array ( [id] => 40 [another_id] => 2805 [third_id] => 2 ) 
    [7] => Array ( [id] => 41 [another_id] => 2805 [third_id] => 2 )
    [8] => Array ( [id] => 42 [another_id] => 2805 [third_id] => 2 ) 
    [9] => Array ( [id] => 43 [another_id] => 2805 [third_id] => 2 )
 )

What I need to do is ultimately print out 9 links ( as there are 9 array elements) but based on the keys in the array. For example:

www.samplelink/link/id/another_id/third_id

But I can't seem to get the loop right. What I have so far is:

foreach ($array as $arr) {
  foreach ( $arr as $key => $value ) {
    echo "<a>www.samplelink/link/".$key[$value]."</a>";
  }
}

But thats not exactly what I need as its printing out the keys as well. Anyone know what I could do?

Answer 1

If elements in subarrays always in same order, you can just implode them:

foreach ($array as $arr) {
    echo "<a>www.samplelink/link/".implode('/', $arr)."</a>";
}

Otherwise you should point what index will be in which position explicitly, as in @Danyal Sandeelo's answer.