dongzhan1948 2017-01-16 11:44
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Symfony建设子表格

Im trying to create a special form, first of all I have a form about a professional, and it has experience as a property. I add those values to my form:

$builder->add('job_company');
$builder->add('job_position');

The problem is that I want to be able to generate multiple experiences, with a button. I should use the CollectionType of symphony, but I don't know if I need to create another special form for the experience, so when I click on the button I create those inputs with a different name (this name must be different if I want to validate them).

I've tried to use:

->add('experiences', CollectionType::class, array(
        'entry_type'   => TextType::class,
        'allow_add'  => true,
        'allow_delete' => true,
    ))

But when I try to render it ({{ form_widget(form.experiences)}}), I get these error:

AppBundle\Entity\ProfessionalExperience could not be converted to string

I also tried ({{ form_widget(form.experiences.company)}}) but I can't get this variable.

How can I do it properly?

Thank you for helping.

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  • dsplos5731 2017-01-16 12:16
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    You have declared that you experiences subform is TextType, therefore

    {{ form_widget(form.experiences)}}
    

    is trying to create a simple <input/> field and set its value. The value of input is a simple string while you're providing AppBundle\Entity\ProfessionalExperience instance. That's why you're getting this error.

    You don't want it to be TextType. It should be some kind of custom form class like ExperienceType.

    ->add('experiences', CollectionType::class, array(
            'entry_type'   => ExperienceType::class,
            'allow_add'  => true,
            'allow_delete' => true,
        ))
    

    And you should of course create such form class with fields suitable for your AppBundle\Entity\ProfessionalExperience entity

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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