dre26973 2013-08-01 16:41
浏览 41
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CodeIgniter / PHP错误消息

The goal of this application is to be able to click on a link from one view to get data from another. The first view works just fine and I'm getting the correct PK as well. When I click the link I am having issues.

Getting a 'Message: Invalid argument supplied for foreach()' from this view:

<?php
    echo "<h2>View</h2>";
    foreach ($rows as $r){
        echo '<br /><h3>'; echo $r->tHandle; echo'</h3>';
        echo "<li>Sent at:  "; echo $r->content; echo"</li><br />";
        echo'<li>Created:  '; echo $r->created; echo'</li><br />';
    }
?>

This is the model and function where the DB query is taking place:

<?php
class Tweets_model extends CI_Model{

    public function __construct() {

        $this->load->database();

    }

    public function getTweetDetails($id){
    $this->db->select('*')->from('tweets')->where('tweetId', $id);
    $q = $this->db->get();
        if($q->num_rows > 0){

            foreach($q->result() as $row){

                $data[]=$row;

            }
            return $data;

        }

    }
}
?>

Controller:

<?php

class Tweets extends CI_Controller{

    public function __construct() {
        parent::__construct();
        $this->load->model('tweets_model');
    }

    public function details(){

        $data['rows'] = $this->tweets_model->getTweetDetails($this->uri->segment(2));
        $this->load->view('header');
        $this->load->view('tweet_details', $data);
        $this->load->view('footer');
    }
}

?

>

Can anyone help me get past my error message?

Thanks.

  • 写回答

2条回答 默认 最新

  • doumaque6551 2013-08-01 17:03
    关注

    You need to do some troubleshooting here. All your errors are because the database isn't returning any data.

    1. Ensure that the tweetId is actually in segment 2, the segments start counting after the base_url so if your base url is example.com then segment 2 would be something like example.com/tweet/2 with 2 being the right segment.

    2. Pass a tweetId you KNOW exists to the model in this line:

      $data['rows'] = $this->tweets_model->getTweetDetails($this->uri->segment(2));

    So something like:

    $data['rows'] = $this->tweets_model->getTweetDetails(1);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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