dr5648 2016-03-31 16:33
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使用php重定向到另一个html文件

I currently want to redirect to another HTML file (i.e. dashboard.html) after the user has successfully. I know I can use header to solve this, but I am not sure where should I add it into my code.

if (mysqli_query($Link, $Query)) {
        $lastID = mysqli_insert_id($Link);
        $Query2 = "INSERT INTO $table_2 VALUES (NULL,
        '".$lastID."')";
        if (mysqli_query($Link, $Query2)) {
            $message = "You've sucessfully created the account!";
            echo json_encode(array('success'=>'true', 'action'=>'login','html'=>$message, 'console.log'=>$Query));
        }
        else {
            $message = "Error occur in query2";
            echo json_encode(array('action'=>'error','html'=>$message, 'console.log'=>$Query));
        }
    }
    else {
        $message = "Error in query1";
        echo json_encode(array('action'=>'error','html'=>$message, 'console.log'=>$Query));
    }

Cheers for your kindly help.

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3条回答 默认 最新

  • douping5226 2016-03-31 16:50
    关注
    if (mysqli_query($Link, $Query)) {
            $lastID = mysqli_insert_id($Link);
            $Query2 = "INSERT INTO $table_2 VALUES (NULL,
            '".$lastID."')";
            if (mysqli_query($Link, $Query2)) {
                $message = "You've sucessfully created the account!";
                echo json_encode(array('success'=>'true', 'action'=>'login','html'=>$message, 'console.log'=>$Query));
            }
            else {
                $message = "Error occur in query2";
                echo json_encode(array('action'=>'error','html'=>$message, 'console.log'=>$Query));
            }
        }
        else {
            $message = "Error in query1";
            echo json_encode(array('action'=>'error','html'=>$message, 'console.log'=>$Query));
        }
    

    jQuery

    $.ajax( { 
        type: 'POST', 
        dataType: 'json', 
        data: postData, 
        url: 'n3228691.scm.tees.ac.uk/Yii/MACC/models/…';, 
        success: function(data) { 
            console.log(data); 
            if(data.action === "login"){
                window.location="dashboard.html"; //succeed insert
            }else{
                alert('There was an error handling your registration!'); 
            }
        }, 
        error: function(data) { 
            alert('There was an error handling your registration!'); 
        }
    });
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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