douzong5057 2014-06-27 07:27
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使用Ajax将图像传递给PHP

I am trying to pass an image and a title field value to PHP, I usually process file uploads straight with PHP using the $_FILES array, I am not sure how to create/pass this array using ajax to PHP. My form:

<form role="form" name="updateProductForm" id="updateProductForm" method="POST" enctype="multipart/form-data"> 
    <input name="imgOne" id="imgOne" type="file" title="Add Image">
    <a class="btn btn-primary" name="updateProduct" id="updateProduct">Update Product</a></div>
</form>

And I am trying to use this to pass to PHP:

$('#updateProduct').on('click', function() {
    try {
        ajaxRequest = new XMLHttpRequest();
    } catch (e) {
        try {
            ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
        } catch (e) {
            try {
                ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
            } catch (e) {
                alert("Your browser broke!");
                return false;
            }
        }   
    }
    ajaxRequest.open("POST", "../Controller/ProductController.php", true);
    ajaxRequest.setRequestHeader("Content-type","application/x-www-form-urlencoded");
    ajaxRequest.send("title=" + $("#title").val() + "&imgOne=" + $("#imgOne"));

    // Create a function that will receive data sent from the server
    ajaxRequest.onreadystatechange = function(){
        if(ajaxRequest.readyState == 4){
            console.log(ajaxRequest);
        }
    }

});

In PHP I am trying this:

if (isset($_POST["edit"])) {
    $id = $_POST["edit"];
    $imgName = $_FILES["file"]["imgName"];
}

Youssef

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3条回答 默认 最新

  • dongxiong1935 2014-06-27 07:47
    关注

    I did that in one of my project, and following code works for me. Please do required modifications in code as your need.

    My Form button:

     <form name="upload_img" enctype="multipart/form-data" id="upload_img">
    <input type="file" style="display:none" id="upload-image" name="upload-image"></input>
    <button id="upload_image" type="button">Save</button>
    </form>
    

    My JQuery/Ajax :

    $('#upload_image').click(function()
    {
        var form = new FormData(document.getElementById('upload_img'));
        //append files
        var file = document.getElementById('upload-image').files[0];
        if (file) {   
            form.append('upload-image', file);
        }
        $.ajax({
            type: "POST",
            url: "URL",
            data: form,             
            cache: false,
            contentType: false, //must, tell jQuery not to process the data
            processData: false,
            //data: $("#upload_img").serialize(),
            success: function(data)
            {
                if(data == 1)
                    $('#img_msg').html("Image Uploaded Successfully");
                else
                    $('#img_msg').html("Error While Image Uploading");
            }
        });
        //alert('names');
    
    
    });
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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