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G运算应该包含两步：
1. 用随机数B生成密文C，同上面的密码加密过程。
2. 将密文C用公钥（密文D）再次加密，生成密文E。

F运算就是生成密钥的过程。 lcedbug 那就有点难搞了，谢谢啦~ bobhuang 回复lcedbug: 因为密文C/D/E都是160位，猜测F和G是自定义的算法，而不是常见的强加密算法。如果在不知道算法的情况下破解的话，只能用特殊的密文C和明文A去逐步尝试了。 lcedbug 谢谢！您的密码验证过程讲得很详细清晰，我能够理解！我现在是想在设备添加这个功能，但是因为不清楚跟上位机之间的具体解密算法，所以进行不下去~ DES, AES, RSA这些算法密钥都不是160bit的，猜不出怎么算的 bobhuang 回复lcedbug: 按我的理解，把解释补充到回复中了。 lcedbug 加密的算法我已经知道是SHA_1, 但是解密使用的算法并不知道，猜测也是SHA_1，但是找不出输入是什么 RSA 加密算法的计算
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1：以01stream.txt文件,好像不能上传附件，文件内容为01所组成的数据流，为自己所写程序的输入，读取中文件中的01数据流； 2：设定窗口大小1000，以不超过50%的相对误差回答任意时刻，当前窗口中有多少个1-bit； 3：设定窗口大小2000，以不超过10%的相对误差回答任意时刻，当前窗口中有多少个1-bit； 4：编写一个精确计算当前窗口中1-bit个数的精确程序，比较精确程序在运行时间和空间和DGIM算法的差异。 没有头绪，有熟悉这种算法的大神么，谢谢了。 大数据相关的
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CentOS 7.6 64bit with ARM系统下的docker安装mysql失败
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Random Walking 程序思路
Problem Description The Army of Coin-tossing Monkeys (ACM) is in the business of producing randomness. Good random numbers are important for many applications, such as cryptography, online gambling, randomized algorithms and panic attempts at solutions in the last few seconds of programming competitions. Recently, one of the best monkeys has had to retire. However, before he left, he invented a new, cheaper way to generate randomness compared to directly using the randomness generated by coin-tossing monkeys. The method starts by taking an undirected graph with 2n nodes labelled 0, 1, …, 2n - 1. To generate k random n-bit numbers, they will let the monkeys toss n coins to decide where on the graph to start. This node number is the first number output. The monkeys will then pick a random edge from this node, and jump to the node that this edge connects to. This new node will be the second random number output. They will then select a random edge from this node (possibly back to the node they arrived from in the last step), follow it and output the number of the node they landed on. This walk will continue until k numbers have been output. During experiments, the ACM has noticed that different graphs give different output distributions, some of them not very random. So, they have asked for your help testing the graphs to see if the randomness is of good enough quality to sell. They consider a graph good if, for each of the n bits in each of the k numbers generated, the probability that this bit is output as 1 is greater than 25% and smaller than 75%. Input The input will consist of several data sets. Each set will start with a line consisting of three numbers k, n, e separated by single spaces, where k is the number of n-bit numbers to be generated and e is the number of edges in the graph (1 ≤ k ≤ 100, 1 ≤ n ≤ 10 and 1 ≤ e ≤ 2000). The next e lines will consist of two space-separated integers v1, v2 where 0 ≤ v1, v2 < 2n and v1 ≠ v2. Edges are undirected and each node is guaranteed to have at least one edge. There may be multiple edges between the same pair of nodes. The last test case will be followed by a line with k = n = e = 0, which should not be processed. Output For each input case, output a single line consisting of the word Yes if the graph is good, and No otherwise. Sample Input 10 2 3 0 3 1 3 2 3 5 2 4 0 1 0 3 1 2 2 3 0 0 0 Sample Output No Yes

Problem Description For a string of n bits x1, x2, x3, …, xn, the adjacent bit count of the string (AdjBC(x)) is given by x1*x2 + x2*x3 + x3*x4 + … + xn-1*xn which counts the number of times a 1 bit is adjacent to another 1 bit. For example: AdjBC(011101101) = 3 AdjBC(111101101) = 4 AdjBC(010101010) = 0 Write a program which takes as input integers n and k and returns the number of bit strings x of n bits (out of 2n) that satisfy AdjBC(x) = k. For example, for 5 bit strings, there are 6 ways of getting AdjBC(x) = 2: 11100, 01110, 00111, 10111, 11101, 11011 Input The first line of input contains a single integer P, (1 ≤ P ≤ 1000), which is the number of data sets that follow. Each data set is a single line that contains the data set number, followed by a space, followed by a decimal integer giving the number (n) of bits in the bit strings, followed by a single space, followed by a decimal integer (k) giving the desired adjacent bit count. The number of bits (n) will not be greater than 100 and the parameters n and k will be chosen so that the result will fit in a signed 32-bit integer. Output For each data set there is one line of output. It contains the data set number followed by a single space, followed by the number of n-bit strings with adjacent bit count equal to k. Sample Input 10 1 5 2 2 20 8 3 30 17 4 40 24 5 50 37 6 60 52 7 70 59 8 80 73 9 90 84 10 100 90 Sample Output 1 6 2 63426 3 1861225 4 168212501 5 44874764 6 160916 7 22937308 8 99167 9 15476 10 23076518
Calculator 计算器的问题
Problem Description The users feedback for your most beloved open-source operating system is gathered, and guess what the most required feature turned out to be? Yes it is finally what we all have been waiting for so long, extending the built-in calculator functionality! On of the suggested extensions is adding the capability of evaluating polynomials, and that’s what you are thrilled to participate with! In this problem you’re given a polynomial entered by the user in the calculator and are asked to evaluate it for a certain value. Input The first line of input contains T (0 < T <= 100) the number of polynomials, each test cases consists of two lines, the first line contains an integer (-1000 <= X <= 1000), the value for the variable X for which the polynomial is evaluated. The second line contains a polynomial P with integer coefficients. P is a sum of terms of the form CX^E , where the coefficient C and the exponent E satisfy the following conditions: 1. E is an integer satisfying (0 <= E <= 30). If E is 0, then CX^E is expressed as C. If E is 1, then CX^E is expressed as CX, unless C is 1 or -1. In those instances, CX^E is expressed as X or -X. 2. C is an integer. If C is 1 or -1 and E is not 0 or 1, then the CX^E will appear as X^E or -X^E. 3. Only non-negative C values that are not part of the first term in the polynomial are preceded by +. 4. Exponents in consecutive terms are strictly decreasing. 5. C fits in a 32-bit signed integer. Output For each test case, print the value of polynomial evaluation. The result will fit in a 32-bit signed integer. Follow the output format below. Sample Input 2 -2 2X^2-5X+7 2 -3X^12+X Sample Output Case #1: 25 Case #2: -12286
Manhattan Sort 程序的思想
Problem Description Yet another sorting problem! In this one, you’re given a sequence S of N distinct integers and are asked to sort it with minimum cost using only one operation: The Manhattan swap! Let Si and Sj be two elements of the sequence at positions i and j respectively, applying the Manhattan swap operation to Si and Sj swaps both elements with a cost of |i-j|. For example, given the sequence {9,5,3}, we can sort the sequence with a single Manhattan swap operation by swapping the first and last elements for a total cost of 2 (absolute difference between positions of 9 and 3). Input The first line of input contains an integer T, the number of test cases. Each test case consists of 2 lines. The first line consists of a single integer (1 <= N <= 30), the length of the sequence S. The second line contains N space separated integers representing the elements of S. All sequence elements are distinct and fit in 32 bit signed integer. Output For each test case, output one line containing a single integer, the minimum cost of sorting the sequence using only the Manhattan swap operation. Sample Input 2 3 9 5 3 6 6 5 4 3 2 1 Sample Output Case #1: 2 Case #2: 9
Big Division 分割的问题
Problem Description A theoretical physicist friend is doing research about the "Answer to the Ultimate Question of Life, the Universe, and Everything", he thinks that it is not 42 as suggested by “The Hitchhiker's Guide to the Galaxy” science fiction comedy series; instead he thinks it is the result of dividing the products of two sequences of positive integers A and B! The task of calculating the product of A and B followed by division turned out to be not as easy as it looks, specially with the sequences being long and the products getting too large very quickly! Even using a modern computer, a straight forward implementation for the calculations may take very long time to complete! And this is where we seek your help as a brilliant computer scientist! Input The first line of input contains an integer (1 <= T <= 200), the number of test cases. T test cases follow, the first line of each test case contains two integers (1 <= N, M<= 110,000), the lengths of sequences A and B respectively. Two lines follow, the first line contains N space separated integers (0 < A0, A1 … An <= 1,000,000), and the second line contains M space separated integers (0 < B0, B1 … Bm <= 1,000,000). Output For each test case, print one line containing the result of dividing the product of sequence A by the product of sequence B as a reduced fraction of the format “X / Y” (Notice the single space before and after the fraction sign). X and Y are guaranteed to fit in 32-bit signed integer. A reduced fraction is a fraction such that the greatest common divisor between the nominator and the denominator is 1. Sample Input 2 3 1 2 4 5 12 2 4 1 15 5 1 7 2 Sample Output Case #1: 10 / 3 Case #2: 3 / 14
Sequence Folding 顺序的序列问题
Problem Description Alice and Bob are practicing hard for the new ICPC season. They hold many private contests where only the two of them compete against each other. They almost have identical knowledge and skills, the matter which results many times in ties in both the number of problems solved and in time penalty! To break the tie, Alice and Bob invented a tie breaker technique called sequence folding! The following are the steps of this technique: 1- Generate a random integer N >= 2. 2- Generate a sequence of N random integers. 3- If N = 2 go to step 6. 4- Fold the sequence by adding the Nth element to the first, the N-1th element to the second and so on, if N is odd then the middle element is added to itself, figure 1 illustrates the folding process. 5- Set N = ceil (N/2) and go to step 3. 6- The sequence now contains two numbers, if the first is greater than the second then Alice wins, otherwise Bob wins. Figure 1.a Before Folding Figure 1.b After one step of folding Figure 1.c After two steps of folding, Alice wins! In this problem you’re given the sequence of N integers and are asked determine the contest winner using the sequence folding tie breaker technique. Input The first line contains T (1 <= T <= 100), the number of test cases. The first line of each test case contains an integer (2 <= N <= 100), the number of elements of the sequence. The next line contains N space separated integers. The sum of any subset of the numbers fit in a 32 bit signed integer. Output For each test case print the name of the winner. Follow the output format below. Sample Input 2 5 2 5 10 3 -4 3 5 4 -3 Sample Output Case #1: Alice Case #2: Bob

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Problem Description "Take 147 steps due north, turn 63 degrees clockwise, take 82 steps, ...". Most people don't realize how important accuracy is when following the directions on a pirate's treasure map. If you're even a tiny bit off at the start, you'll end up far away from the correct location at the end. Pirates therefore use very exact definitions. One step, for instance, has been defined by the 1670 Pirate Convention to be exactly two times the size of the wooden leg of Long John Silver, or 1.183 m in metricunits. Captain Borbassa was thus not at all worried when he set sail to the treasure island, having a rope with knots in it, exactly one step apart, for accurately measuring distances. Of course he also brought his good old geotriangle, once given to him by his father when he was six years old. However, on closer inspection of the map, he got an unpleasant surprise. The map was made by the famous captain Jack Magpie, who was notorious for including little gems into his directions.In this case, there were distances listed such as sqrt(33) steps. How do you measure that accurately? Fortunately, his first mate Pythagor came to the rescue. After puzzling for a few hours, he came up with the following solution: let pirate A go 4 steps into the perpendicular direction, and hold one end of the measuring rope there. Then pirate B goes into the desired direction while letting the rope slide through his fingers, until he is exactly 7 steps away from pirate A. Pythagor worked out a formula that states that pirate B has then traveled exactly sqrt(33) steps. Captain Borbassa was impressed, but he revealed that there were more such distances on the map. Paranoid as he is, he refuses to let Pythagor see the map, or even tell him what other distances there are on it. They are all square roots of integers, that's all he gets to know. Only on the island itself will the captain reveal the numbers, and then he expects Pyhtagor to quickly work out the smallest two integer numbers of steps that can combine to create the desired distance, using the method described above. Pythagor knows this is not easy, so he has asked your help. Can you help him by writing a program that can determine these two integers quickly? By the way, he did ask the captain how large the numbers inside the square root could get, and the captain replied "one billion". He was probably exaggerating, but you'd better make sure the program works. If you can successfully help the pirates, you'll get a share of the treasure. It might be gold, it might be silver, or it might even be... a treasure map! Input The first line of the input contains a single number: the number of test cases to follow. Each test case has the following format: 1.One line with one integer N, satisfying 1 <= N <= 10^9. Output For every test case in the input, the output should contain two nonnegative integers, separated by a space, on a single line: the distance pirate A needs to head in the perpendicular direction, and the final distance between pirate A and B, such that pirate B has traveled sqrt(N) steps. If there are multiple solutions, give the one with the smallest numbers. If there are no solutions, the output should be "IMPOSSIBLE" (without the quotation marks) on a single line. Sample Input 4 33 16 50 101 Sample Output 4 7 0 4 IMPOSSIBLE 50 51
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Parking Ships 问题求解
Problem Description Life on the great oceans has been good for captain Blackbeard and his fellow pirates. They have gathered so many treasures, that each of them is able to buy a house on their favorite island. The houses on this island are all placed in a long row along the beach line of the island. Next to a house, every pirate is also able to buy his own ship to do their own bit of plundering. However, this causes a whole new kind of problem. Along the beach line there is a long pier where every pirate can park his ship. Although there is enough space along the pier for all the ships, not every pirate will be able to park in front of his house. A pirate is happy with his parking space if some part of the parking space is in front of the center of his house. Captain Blackbeard has been given the diffcult task of assigning the parking spaces to the pirates. A parking space for a pirate i is a range [ai, bi] (ai, bi∈R) along the pier such that li<= bi - ai, where li is the length of the ship of pirate i. Thus, pirate i is happy if ai <= xi <= bi, where xi is the center of the house of pirate i. Clearly, parking spaces of different pirates must be interior disjoint (the ends of ranges can coincide). Above all, the captain wants a good parking space for himself, so he gives himself the parking space such that the center of his ship is aligned with the center of his house. Next to that, he wants to make as many pirates happy as possible. Can you help him out? Input The first line of the input contains a single number: the number of test cases to follow. Each test case has the following format: 1.One line with one integer n (1 <= n <= 1,000): the number of pirates including the captain. 2.n lines with on each line two integers xi (-10^9 <= xi <= 10^9) and li (1 <= li <= 10^9): the center of the house of the ith pirate and the total length of his ship, respectively. The first pirate in the input is always the captain. Output For every test case in the input, the output should contain one integer on a single line: the maximum number of happy pirates using an optimal assignment of the parking spaces. This number includes the captain himself. You can assume that the space along the pier is unbounded in both directions. Sample Input 2 5 0 6 -5 2 -4 1 4 2 5 3 4 0 4 -5 4 3 4 5 3 Sample Output 5 3
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