doucitan2544 2015-07-09 19:06
浏览 9
已采纳

为什么PHP认为我的日期是一个字符串?

My code is giving me the error "Fatal error: Call to a member function sub() on string" As you can see the $date variable is a string based on the echo, but it still believes it to be a string.

My code:

echo $stringDate;
    //PRINTS "2014-03-27"
$date = date('yyyy-mm-dd', strtotime( $stringDate );
echo $date;
    //PRINTS "14141414-0303-2727"
$date->sub(new date_interval_create_from_date_string('70 days') );
    //Produces "Fatal error: Call to a member function sub() on string"
$milestones["Method Development Checklist"]['date'] = $date;
  • 写回答

1条回答 默认 最新

  • dongping9475 2015-07-09 19:11
    关注

    Instead of

    date('yyyy-mm-dd', strtotime( $stringDate ));
    

    use

    date_create_from_format("Y-m-d", $stringDate);
    

    which is an alias for

    DateTime::createFromFormat("Y-m-d", $stringDate);
    

    Have a nice day o/

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥170 如图所示配置eNSP
  • ¥20 docker里部署springboot项目,访问不到扬声器
  • ¥15 netty整合springboot之后自动重连失效
  • ¥15 悬赏!微信开发者工具报错,求帮改
  • ¥20 wireshark抓不到vlan
  • ¥20 关于#stm32#的问题:需要指导自动酸碱滴定仪的原理图程序代码及仿真
  • ¥20 设计一款异域新娘的视频相亲软件需要哪些技术支持
  • ¥15 stata安慰剂检验作图但是真实值不出现在图上
  • ¥15 c程序不知道为什么得不到结果
  • ¥15 键盘指令混乱情况下的启动盘系统重装