dtmsaqtly798322992
dtmsaqtly798322992
2015-11-04 10:48

使用参数从另一个调用PHP脚本并获取输出

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I have a php script, let's call it one.php. This calls a second php script two.php with some arguments. Right now my code in one.php looks like this:

shell_exec("php ./two.php" . ' ' . escapeshellarg($var1) . ' '.      
escapeshellarg($var2) . ' '. escapeshellarg($var3));

This works fine (although I don't like it), but now I want to get some values that are computed in two.php.

I colud use include() or require() to get access to all the variables, but I want to use two.php in more than just one script - without having to use the same variable names in every script that calls two.php (which I had to because of the scope of the variables in include()).

My php skills are quite poor, so: Is there a way to send variables of a called script to the calling script or something like this? Or maybe another way of calling two.php.

Update: Using a function did it. Thanks!

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1条回答

  • doutuo6689 doutuo6689 6年前

    "Calling another script" via shell_exec is a pretty bad idea. Instead, two.php should contain a bunch of functions or classes which you can include and call anytime:

    include 'two.php';
    
    $data = func_from_two($var1, $var2, $var3);
    

    Learn to program using functions and classes, that's the only sane way to go.

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