dqx13503925528 2015-04-07 16:32
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使用$ variable目录计算所有图像文件的PHP glob()不起作用

with PHP, I need to count all images in a certain directory, given by a variable $filedir, and store this count in a variable $imagecount.

Therefor, I'm using the following:

$fileurl = $file->url();

This variable gives the path to the file's directory like: /mnt/web5/d1/87/52146187/htdocs/bahrain/content/1-pavilion/3-phoenix-dactylifera

$imagecount = count(glob($filedir . '/*.{jpg,jpeg,png,gif}', GLOB_BRACE));

This should count all files of the type jpg, jpeg, png, gif

As a result, I'm always receiving "0" for $imagecount. Does anyone know, what the problem might be? (There are some given image-files in this directory)

Thanks!

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  • dongyin5516 2017-02-26 03:10
    关注

    Use chdir() to set your desired directory.

    <?php
    echo getcwd(),"<br>";  // where you start from
    chdir($filedir);       // where you want to look
    echo getcwd(),"<br>";  // see if you actually got there
    $image_count=count(glob("*.{jpg,jpeg,png,gif}",GLOB_BRACE);
    echo "$image_count";
    ?>
    
    评论

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