选择仅存在日期的所有日期

Question

I know this code works:

$eventdate = new DateTime($event['date']);
$datenow = new DateTime();

if($eventdate->format('Y-m-d') < $datenow->format('Y-m-d')) ....

I need to do something similar in an SQL query.

Something like:

SELECT * FROM MyTable WHERE `date` = `$eventdate` or Future Date

How can I do this?

Answer 1

$sql = "
    SELECT * 
    FROM MyTable 
    WHERE 
        `date` = '{$eventdate->format('Y-m-d')}' OR 
        `date` >= CURDATE()
";

or

$sql = "
    SELECT * 
    FROM MyTable 
    WHERE 
        `date` = '{$eventdate->format('Y-m-d')}' OR 
        `date` >= '{$datenow->format('Y-m-d')}'
";