mysqli - mysqli_stmt :: bind_param（）应该是一个参考

Question

This is my class code:

class DAL
{

public function paramtypez($val)
{
        $types = '';                        //initial sting with types
        foreach($val as $para) 
        {     
            if(is_int($para)) {
                $types .= 'i';              //integer
            } elseif (is_float($para)) {
                $types .= 'd';              //double
            } elseif (is_string($para)) {
                $types .= 's';              //string
            } else {
                $types .= 'b';              //blob and unknown
            }
        }
        return $types;
}

 public function execsql($query,$param)
{
    $conn=new mysqli("127.0.0.1","root","","sample");

    if($row=$conn->prepare($query))
    {
        array_unshift($param,array(DAL::paramtypez($param)));
        call_user_func_array(array($row, 'bind_param'), $param);

        $row->execute();
        return true;
    }
    else
    return false;

}
}

and is use this class like this:

$vars = new DAL();
$vars->execsql('insert into tesst (name,family,age) values(?,?,?)',array('mori','gre','25'));

but that's return me this error:

 Warning: Parameter 2 to mysqli_stmt::bind_param() expected to be a reference, value given in ..\htdocs\inc.php on line 30

how can fix this error? thanks for any help

Answer 1

$param looks like this right before you pass it to call_user_func_array:

[['ssi'],'mori','gre','25']

This is incorrect. You should change this:

array_unshift($param,array(DAL::paramtypez($param)));

To this:

array_unshift($param,DAL::paramtypez($param));